Latest Contributions by anonymous55

Hello, I am getting this error with your code ConnectionError: A connection error has occurred: HTTPSConnectionPool(host='myorg.maps.arcgis.com', port=443): Max retries exceeded with url: /sharing/rest/generateToken (Caused by NewConnectionError('<urllib3.connection.HTTPSConnection object at 0x000001EB4CC5F448>: Failed to establish a new connection: [WinError 10060] A connection attempt failed because the connected party did not properly respond after a period of time, or established connection failed because connected host has failed to respond')) any suggestions? ... View more

I checked and I don't miss anything seems "f" doesn't work here  txtFileNameNoExt = f"{os.path.splitext(txtFileNameWithExt)[0]}_{datetime.datetime.now():%Y_%m_%d}" ^ SyntaxError: invalid syntax also here arcpy.env.workspace = my_Path arcpy.Rename_management(txtFileNameWithExt,f"{txtFileNameNoExt}.shp")   ... View more

Hello @KimGarbade  I don't way but I run your code on jupyter notebook on Arcpro and works fine when I am trying to run on PyScripter I am getting error  #rename shapefile txtFileNameWithExt = "op.shp" txtFileNameNoExt = f"{os.path.splitext(txtFileNameWithExt)[0]}_{datetime.datetime.now():%Y_%m_%d}" arcpy.env.workspace = my_Path arcpy.Rename_management(txtFileNameWithExt,f"{txtFileNameNoExt}.shp")   ... View more

Hello  I shared Analyze page with some users but we can't see some fields?  and shows this. What is of meaning of this? I didn't find anything about those dot in green area.  ... View more

Hello All I am trying to create zip file with name and current date.  example: Land_01242022.zip  I created shapefile with current date like this Land_todayDate.shp. But I am having problem to have same format for zip file with all shapefile on it. I want something like this : Land_todaydate.zip I have this code but this just create zip file with name and not adding date to it. Expression: zipshape(r"Path","Name") this function requires the two inputs folder (path to the shapefile) and name (shapefilename, for example if your shapefile is foo.shp, the name should be foo (without the extension). it doesn't work with one input. code Block: import os import glob import zipfile def zipshape(folder, name): os.chdir(folder) zipname = name + ".zip" flist = glob.glob(name + "*") with zipfile.ZipFile(zipname, "w") as newzip: for ff in flist: if ff[-4:] != "lock" and ff != zipname: newzip.write(ff) return os.path.join(folder, zipname) Date Type File I need to run this everyday because I need to add date or maybe just overwrite pervious zip file with new date.   ... View more

@curtvprice  Thanks a lot I can create zip file right now. Just one question do you know how can rename the zip file which I created rename with current date land_TodayDate.zip.   ... View more

I created shape file and added date whenever you run the model. Right  now I am trying to zip the shapefile and then next step rename it like this : "A_todaydate" I don't understand this part. what I need to replace.  how can I get already shapefile created and zip it.       ... View more

Hello I can create zip file but the zip file is empty. zipshape(r"E:\mypath","open") ... View more

Hello I am having problem to add date to my file I am getting this error in ArcPro     I am having problem to set copy features output. I tried with code here too ... View more

Hello all I have these so have and I am getting this error: JS Code   function returnFeatures2(ID,Token){ var xmlhttp = new XMLHttpRequest(); var token = Token // This is a field token calculation var url = "https://services.arcgis.com/*****/ArcGIS/rest/services/******/FeatureServer/0" +"query?where=vehicle_id%3D%27" + ID // The parameter filter + "%27&objectIds=&time=&resultType=none&outFields=*&returnHiddenFields=false&returnIdsOnly=false&returnUniqueIdsOnly=false&returnCountOnly=false&returnDistinctValues=false&cacheHint=false&orderByFields=&groupByFieldsForStatistics=&outStatistics=&having=&resultOffset=&resultRecordCount=&sqlFormat=none&f=pjson" + "&token=" + token xmlhttp.open("GET",url,false); xmlhttp.send(); if (xmlhttp.status!=200){ return "Error1" } else { var outValue = xmlhttp.responseText; } return outValue; }   Xlsx Form   ... View more

I am thinking my code is not correct I will test it  Thanks a lot ... View more

@Ming  Man This is so confusing I don't know js 🙂  ... View more