Latest Contributions by ThomasColson

With the following set up: MS SQL 2008 R2 A versioned feature class Windows ACL Group "Users" mapped to DBO and full control of all tables Users in "Users" can access and adit the FC through Arc Map SQL Geodatabase successfully registered and validated in the data store Arc GIS Server Windows Domain User Store Windows Domain Role Store Authentication Tier = Web Authentication Mode = Web The "Users" group has been granted access through web-based ArcGIS Server Manager to: A map service a Geodata service IIS Anon Authentication Disabled Windows Authentication Enabled A folder called "Folder" to which the "Users" group has been granted access This setup has worked well for non-SQL-backed map and geodata services. Here's the problem: I create a simple flexviewer app (3.2) with the feature service, using http://localhost/arcgis/rest/services/CRGIS_EDIT/ In the "Preview" tab I can successfully view and edit the data, everything works peachy config.xml reflects "localhost", so in order to see the app from another computer, I edit config.xml to read http://[FQDN]/arcgis/rest/services/CRGIS_EDIT/FeatureServer/0 Which returns the following error: Architectural Survey Line layer failed to load: Fault code: Channel.Security.Error Fault info: Security error accessing url Fault details: Destination: DefaultHTTP Research suggests I should be using Crossdomain.xml, which I've copied to just about every single folder there is, same problem. When using http://[FQDN]/arcgis/rest/services/CRGIS_EDIT/ to define the operational layer in the Flexviewer builder, using the ArcGIS admin account or my windows account will allow access to the service. I can view http://[FQDN]/arcgis/rest/services from any browser, any computer, no problem. Clearly I'm missing something obvious here, what is it? We cannot use local security per organizational policy, it's Windows AD or nothing. Thanks! ... View more

I have a feature Layer: RoadCenterline_Ground_and_Above_1K (ID: 10) and a related table Layer: Route_ID (ID: 148). Within a file geodabase a1:1  relationship exists between the two using the ROUTE_IDENT field, and inspecting the relationship works flawlessly in ArcMap. Standing up   <url>http://grsmgis.nps.gov/arcgis/rest/services/Base/Base/MapServer/10</url> using a Flex Viewer also works fine. As soon as I add    <relates>     <relate id="148" label="Route_ID" enableexport="true" enableprintgrid="true"      icon="assets/images/i_flag.png" printtitle="Routes">      <fields all="false">       <field name="ROUTE_IDENT" />       <field name="RTE_NAME" />      </fields>     </relate>    </relates> the search results indicate related records but the related record datagrid does not populate, nor does clicking on the related record icon return anything. Yes, I  have confirmed that there is indeed a related record for each feature. This is on Arc GIS Server 10.1, SP1, Flex 3.1. ... View more

Does build 2500 have an install setup that allows install without admin rights, as did 1750? ... View more

I'm sure someone has figured this out....how can I depict one-way travel direction indicators as a symbol (inside a cased street symbol, for example)? This is in 10.1, with geodatabase data providing road centerlines, with a one-way (from-to, to-from, unknown) attribute. In addition, we are also using route shields and road names. ... View more

I suppose there's a really easy answer to this, I just can't find it! I have a 3D line FC with Z values, for which I need to derive the midpoint using 3D length. This is in very, very mountainous terrain, and the 3d length is substantially different from the 2 length. I tried adding a X and Y midpoint field, to later convert to a point FC, but that is only using 2d values. The split tool in the Arc Scene Editor Toolbar also (surprisingly) splits on 2D length, not 3D, as verified by determining 3D and 2D segement lengths after the split (2D was the same for each line half, 3D substantially different for each line half). Wishfully hoping there's a tool or script that does this, but a method of calculating 3D mid x and y will get me what I need. THanks! ... View more