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Raster Domain python script change output location

Question asked by gadoury.j on Nov 27, 2018
Latest reply on Nov 28, 2018 by jskinner-esristaff

I have a folder tree with many other folders in it containing many images. I have managed to make a script that will parse through the entire folder and find every image in it. It then uses raster domain to create a polygon shapefile of every footprint for each image.

 

The issue I am having is I need to have those footprints exported to a single folder named "index". The current script always exports the footprints to the same folder the image is located in. How can I change my script to export the raster domain footprints to the "index" folder instead of them being exported to the folder containing the imagery?

 

Here is my script:

 

import arcpy

import os

 

workspace = r”D:\Folder\Test”

outFile = r”D:\Folder\Index”

 

rasters = []

 

arcpy.CheckOutExtension(“3D”)

 

print ‘Processing’

 

for dirpath, dirnames, filenames, in arcpy.da.Walk(workspace, topdown=True, datatype=”RasterDataset”):

                for filename in filenames:

                                rasters.append(os.path.join(dirpath, filename))

 

for raster in rasters:

                outGeom = “POLYGON”

                outPoly = raster[:-4]+”.shp”

                arcpy.RasterDomain_3d(raster, outPoly, outGeom)

 

print rasters

 

print ‘Completed’

 

 

I'm pretty sure the answer lies with changing the "outPoly" parameter but anything I have tried resulted in an error. Any help would be much appreciated.

 

Thank you for your time.

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