Latest Contributions by AnnetteLocke

Can you use this workaround?  private Multipart GetOffsetUsingGraphicBuffer(Multipart multipart, double offsetDistance, LineJoinType joinType) { Polygon graphicBuffer = GeometryEngine.Instance.GraphicBuffer(multipart, Math.Abs(offsetDistance), joinType, LineCapType.Square, 4, 0, 96) as Polygon; Polyline boundary = GeometryEngine.Instance.Boundary(graphicBuffer) as Polyline; ProximityResult startResult = GeometryEngine.Instance.NearestPoint(boundary, multipart.Points[0]); Coordinate2D coord = (Coordinate2D)(startResult.Point); Segment firstSegment = multipart.Parts[0][0]; // Negative offset distance means the offset line will be on the left side bool isOnRightSide = PointIsOnRightSide(firstSegment.StartCoordinate, coord, firstSegment.EndCoordinate); if (offsetDistance > 0 && !isOnRightSide) coord.Rotate(Math.PI, (Coordinate2D)(multipart.Points[0])); double distanceAlongCurve1, distanceFromCurve; LeftOrRightSide whichSide; MapPoint point = GeometryEngine.Instance.QueryPointAndDistance(boundary, SegmentExtensionType.NoExtension, coord.ToMapPoint(), AsRatioOrLength.AsRatio, out distanceAlongCurve1, out distanceFromCurve, out whichSide); ProximityResult endResult = GeometryEngine.Instance.NearestPoint(boundary, multipart.Points.Last()); coord = (Coordinate2D)(endResult.Point); if (offsetDistance > 0 && !isOnRightSide) coord.Rotate(Math.PI, (Coordinate2D)(multipart.Points.Last())); double distanceAlongCurve2; point = GeometryEngine.Instance.QueryPointAndDistance(boundary, SegmentExtensionType.NoExtension, coord.ToMapPoint(), AsRatioOrLength.AsRatio, out distanceAlongCurve2, out distanceFromCurve, out whichSide); double d1 = Math.Min(distanceAlongCurve1, distanceAlongCurve2); double d2 = Math.Max(distanceAlongCurve1, distanceAlongCurve2); Polyline subCurve = GeometryEngine.Instance.GetSubCurve(boundary, d1, d2, AsRatioOrLength.AsRatio) as Polyline; return subCurve; } private bool PointIsOnRightSide(Coordinate2D origin, Coordinate2D p1, Coordinate2D p2) { // The result is positive if p1 lies on right side of origin-->p2; double part1 = (p1.X - origin.X) * (p2.Y - origin.Y), part2 = (p1.Y - origin.Y) * (p2.X - origin.X), result = part1 - part2; return result > 0; } // Here is a test public void GEOffsetWorkaroundTest() { SpatialReference spatialReference = SpatialReferences.WGS84; var coords = new List<Coordinate2D> { new Coordinate2D(0.1, 0.1), new Coordinate2D(0.2, 0.5), new Coordinate2D(0.3, 0.1), new Coordinate2D(0.4, 0.1), new Coordinate2D(0.5, 0.8) }; Polyline polyline = PolylineBuilderEx.CreatePolyline(coords, spatialReference) as Polyline; Polyline outputOffsetPolyline = GetOffsetUsingGraphicBuffer(polyline, 0.1, LineJoinType.Miter) as Polyline; File.WriteAllText("C:\\temp\\outputOffsetPolyline_1_.txt", outputOffsetPolyline.ToJson()); outputOffsetPolyline = GetOffsetUsingGraphicBuffer(polyline, -0.1, LineJoinType.Miter) as Polyline; File.WriteAllText("C:\\temp\\outputOffsetPolyline_2_.txt", outputOffsetPolyline.ToJson()); outputOffsetPolyline = GetOffsetUsingGraphicBuffer(polyline, 0.1, LineJoinType.Bevel) as Polyline; File.WriteAllText("C:\\temp\\outputOffsetPolyline_3_.txt", outputOffsetPolyline.ToJson()); outputOffsetPolyline = GetOffsetUsingGraphicBuffer(polyline, -0.1, LineJoinType.Bevel) as Polyline; File.WriteAllText("C:\\temp\\outputOffsetPolyline_4_.txt", outputOffsetPolyline.ToJson()); outputOffsetPolyline = GetOffsetUsingGraphicBuffer(polyline, 0.1, LineJoinType.Round) as Polyline; File.WriteAllText("C:\\temp\\outputOffsetPolyline_5_.txt", outputOffsetPolyline.ToJson()); } ... View more

This is a bug that will be addressed in a future release. Unfortunately, I can't give you an exact date at this time. I am working on a workaround for you, but I want to test it a little bit more. It will be ready tomorrow.  Regarding SideBuffer, the corners of the buffer will always be round. The LineCapType refers only to the start and end of the line.    ... View more

Hi, I am looking into this. I will respond shortly. Thank you, Annette ... View more

Hi Steve, the patch has not been released yet, but it is coming soon. If you have the SDK installed, Visual Studio has a notification icon that will tell you that an update is available. Also, there is an option in the IDE to "automatically update extensions". If that option is turned on, then you don't have to do anything - it will get automatically updated. Thanks, Annette ... View more

Hi Matthias, The input polyline should be known simple before calling Cut. You can do this by calling either GeometryEngine.Instance.IsSimpleAsFeature (if you know that it is simple) or GeometryEngine.Instance.SimplifyAsFeature (if you're not sure if it is simple or not).  For future reference, if a GeometryEngine method throws a GeometryObjectException with the message "GeometryObjectException: The operation cannot be performed on a non-simple geometry.", then the geometry needs to be known simple. The doc should explicitly mention this, so we will update it. Thank you for pointing it out.  Let me know if you have any questions. Annette ... View more

In the meantime, you could insert the geometries into a feature class in a geodatabase and use the GeoProcessing tool CheckGeometry.  https://pro.arcgis.com/en/pro-app/latest/tool-reference/data-management/check-geometry.htm ... View more

Hi Kirk, The Pro SDK doesn't have it, but we do have an issue in our queue to add it. I will update the priority to include it in an upcoming release. Thanks, Annette ... View more

Hi Kris, The domain extent is different than the valid area of a coordinate system. The domain extent is an arbitrary square used to delimit valid coordinates for a spatial reference system and determine their resolution. It is possible that the domain extent is larger than the usable area of a coordinate system (a UTM zone, for example). I suspect that what you are looking for is the horizon. We plan to add a method to get the horizon in a near-term release. In the meantime, you can take a look at https://community.esri.com/message/935357-re-how-to-get-the-spatialreference-horizon-polygon  for a possible workaround.  I hope that helps.  Thanks, Annette ... View more

Alan, You are right. This won't work for the reason that you stated. We will add a method to get the horizon from the spatial reference in a near-term release.  Thank you, Annette ... View more

Hi Alan, I will take a look and get back to you.  Thanks, Annette ... View more