Latest Contributions by DonMorrison1

I'm packaging a project with an embedded python toolbox with the intent of sharing it with others via ArcGIS Online. The python tool imports a module and it looks like the path to that module is being incorrectly changed during consolidation. The path to the imported module as I created it is: E:\ROW_as_habitat\temp\test_dir The path after the consolidation(I ran Package Product, uploaded the .ppkx to ArcGIS Online, then open the uploaded .ppkx in ArcGIS Online via the portal) is  C:\Users\DMORRI~1\AppData\Local\Temp\ArcGISProTemp1188\..\test_project_1\p20\test_dir I would expect the fixed up path to point into the Packages directory, but this is pointing into the temp directory. I do see the module in what I believe is the proper place in under the Packages directory. In any case the import fails when I run the tool from the packaged project.  Here is the tool code as I created it in ArcGIS Pro # -*- coding: utf-8 -*- import arcpy class Toolbox(object): def __init__(self): self.label = "Toolbox" self.alias = "" self.tools = [Tool] class Tool(object): def __init__(self): self.label = "Tool" self.description = "" self.canRunInBackground = False def getParameterInfo(self): params = None return params def isLicensed(self): return True def updateParameters(self, parameters): return def updateMessages(self, parameters): return def execute(self, parameters, messages): test_dir = r'E:\ROW_as_habitat\temp\test_dir' arcpy.AddMessage(test_dir) sys.path.append(test_dir) import logger as row_logger arcpy.AddMessage(row_logger.LOG_FILE) return‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍ Here is the code after the fixup # -*- coding: utf-8 -*- # # Esri start of added imports import sys, os, arcpy # Esri end of added imports # Esri start of added variables g_ESRI_variable_1 = os.path.join(arcpy.env.scriptWorkspace,'..\\test_project_1\\p20\\test_dir') # Esri end of added variables # -*- coding: utf-8 -*- import arcpy class Toolbox(object): def __init__(self): self.label = "Toolbox" self.alias = "" self.tools = [Tool] class Tool(object): def __init__(self): self.label = "Tool" self.description = "" self.canRunInBackground = False def getParameterInfo(self): params = None return params def isLicensed(self): return True def updateParameters(self, parameters): return def updateMessages(self, parameters): return def execute(self, parameters, messages): test_dir = g_ESRI_variable_1 arcpy.AddMessage(test_dir) sys.path.append(test_dir) import logger as row_logger arcpy.AddMessage(row_logger.LOG_FILE) return‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍ ... View more

I've been fighting with a problem where I could not package one of my tools as a geoprocessing package. After lots of trial and error I found that it was connected to a totally innocuous try/except in my code.  When the try/except is in the code (see below - for illustration purposes only),  the publishing fails with an error message that provides no clue.  I noticed at some point that if I highlight the problem tool in the Catalog then click Properties -> Parameters I get this message When I remove the try/except, I can view the properties OK, and more importantly the publish works.  I'm not a python expert so maybe there is a good explanation about how a try statement like that could have such a side effect - I'd love to hear it.  For my tool I was able to do some recoding and get around the problem.  But if you are having trouble with publishing, perhaps a good test is to make sure the tools parameters are viewable via the tool properties. import arcpy class Toolbox(object): def __init__(self): self.label = "Toolbox" self.alias = "" self.tools = [TestBoolean] class TestBoolean(object): def __init__(self): self.label = "Tool" self.description = "" self.canRunInBackground = False def getParameterInfo(self): layer = arcpy.Parameter(displayName="Feature Layer", name="layer", datatype="GPFeatureLayer", parameterType="Required", direction="Input") checkbox = arcpy.Parameter(displayName="Checkbox", name="checkbox", datatype="GPBoolean", parameterType="Required", direction="Input") checkbox.value = False params = [layer, checkbox] for param in params: try: filter_list = str(param.filter.list) except Exception: filter_list = 'Can not access' return params def isLicensed(self): return True def updateParameters(self, parameters): return def updateMessages(self, parameters): return def execute(self, parameters, messages): return‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍ I'm running this on ArcPro  2.4.3  and Python 3.6.8 and Advanced license. ... View more