Request Module Try Except Error

[JaredPilbeam2]

What do you do when you catch a Requests exception and you want to identify the URL that caused it? This script loops through a list of URLs and scrapes certain text. If one of the URLs fail in any way I catch it the Try Except block. All I can do now is print the "request error" string.

for url in urls: #iterate through list of URLs
    try:
        #download the homepage
        response = requests.get(url)
        #parse the downloaded homepage and grab all text
        soup = BeautifulSoup(response.text, "lxml")
        #find sought after text
        item = soup.find(string=re.compile("Grab and Go")) if soup.find(string=re.compile("Grab and Go")) else "N/A"
        print(item)
    #catch any request error 
    except requests.exceptions.RequestException:
        print("request error")‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

How can I identify the URL causing that error? Maybe something like:

except requests.exceptions.RequestException:
    print("request error: {}".format(#URL that caused error))‍‍

[Luke_Pinner · Accepted solution]

Something simple like the following perhaps? So you don't completely hide the actual error as well.

except requests.exceptions.RequestException as err:
    print(err, url)