Instantiate TIN as Layer object - arcpy

[martinaraffellini]

Hello! the following commands works with shapefiles and rasters, but i cannot manage with a TIN.

Do you know the reason?

tin = C:\PROJECT\mytin

arcpy.CreateTin_3d(tin, CoordSys, Input_Features)  # coord sys and input defined above

mylayer = arcpy.mapping.Layer('{0}'.format(tin))‍‍‍‍‍

I get an error: invalid data source.

So i tried to save the TIN as a .lyr files first with arcpy.SaveToLayerFile_management(tin), but i get the same error.

With rasters and shapefiles i just give in input the full path of the file, but about the tin?

Thank you!

[IanMurray]

Seems as though you aren't the only person to come up with this issue.

https://community.esri.com/thread/161557

https://community.esri.com/thread/189604-how-do-i-add-a-tin-to-arcmap-using-python