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apologies, I snagged the wrong ID. I can't find it in the list either, so it must be new. I checked the Support site (public facing only) and 001824 isn't listed, but 001823 and 001825 are. So either the number is wrong, or it hasn't made it to the error list yet. Nothing obvious appeared for CreateMobileMapPackage on the support site, but if you haven't looked, it might be worth looking at the entries (Errors or Bug or Community posts) Esri Support Search Results
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01-30-2026
07:04 PM
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The process is here, are you selecting the gdb in the Databases section of catalog? Rename a geodatabase—ArcGIS Pro | Documentation
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01-30-2026
06:43 PM
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Split By Attributes (Analysis)—ArcGIS Pro | Documentation works for a featureclass or table, assuming your attribute you want to split on are based on unique combinations within the attribute field or fields
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01-30-2026
12:24 PM
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if your data are in tabular format Bearing Distance To Line (Data Management)—ArcGIS Pro | Documentation with the intersection to remain
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01-30-2026
09:15 AM
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000184: Spatial index does not exist.—ArcGIS Pro | Documentation if you need one Add Spatial Index (Data Management)—ArcGIS Pro | Documentation there are other links on "Spatial Index" in the help files that may be applicable to your situation
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01-30-2026
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which tool? was there an error number? what was the expression? visuals might help
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01-30-2026
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are you using Generate Points Along Lines (Data Management)—ArcGIS Pro | Documentation or Generate Points Along 3D Lines (3D Analyst)—ArcGIS Pro | Documentation What do you mean by inconsistent results?
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01-30-2026
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Pro comes with python installed. Did you read some of the basic information? ArcGIS Pro Python reference—ArcGIS Pro | Documentation Python in ArcGIS Pro—ArcGIS Pro | Documentation Just follow the links on setting up you IDE and whether you want to install packages in a cloned environment. The base package setup is in the arcgispro-py3 location.
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01-30-2026
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is "Length" and existing field name in the geodatabase? (checking for a reserved word trigger), if it isn't try using a different name. There are no publicly facing bugs bugs on the Support web site for this version of Pro
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01-29-2026
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You have tried all the referenced suggestions and the bug, so I would copy the source geodatabase to a computer with a newer version of Pro to test. Otherwise contact Tech Support since something may apply to Pro 3.2 that has been addressed already
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01-29-2026
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which can be done using numpy as well. an old missive Generate Near Table for points - Esri Community and a newer one Really close points - Esri Community
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01-29-2026
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If you get bogged down on any details, give us a buzz. on that note, arc returns "structured" arrays, since you want just the coordinates, here is a final tip for now. # -- points in arc** format
pnts_arc
array([( 8.78, 91.06), (30.24, 8.75), (98.45, 77.13), (18.81, 49.23),
( 5.66, 19.19), (57.84, 62.84), (93.75, 98.79), (88.83, 44.78),
(52.11, 85.75), (32.27, 37.44)],
dtype=[('SHAPE@X', '<f8'), ('SHAPE@Y', '<f8')])
# -- a quick import and conversion to get an unstructured array to work with
from numpy.lib.recfunctions import unstructured_to_structured as uts
pnts_numpy = stu(pnts_arc)
pnts_numpy
array([[ 8.78, 91.06],
[30.24, 8.75],
[98.45, 77.13],
[18.81, 49.23],
[ 5.66, 19.19],
[57.84, 62.84],
[93.75, 98.79],
[88.83, 44.78],
[52.11, 85.75],
[32.27, 37.44]])
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01-28-2026
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You can read from the featureclass (fc) what you want array = arcpy.da.FeatureClassToNumPyArray(fc, ["OID@", "SHAPE@XY"]) # oid and paired coordinates
array = arcpy.da.FeatureClassToNumPyArray(fc, ["SHAPE@X","SHAPE@Y"]) # just the x, y as separate fields
# "some!!!" of the possibilities are in the code samples
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01-28-2026
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FeatureClassToNumPyArray FeatureClassToNumPyArray—ArcGIS Pro | Documentation can replace the searchcursor and the resultant array can be queried should you need to check other attributes. There has been some generalities here since your original question was solely about coordinates
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01-28-2026
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import numpy as np
pnts = np.random.rand(10,2) * 100
pnts = np.round(pnts, 2) # 2 decimal precision
p = pnts[2] # -- take a sample point (2nd position)for testing inclusion/equality
np.isin(p, pnts).all(-1) # are both x and y coordinates the same
True
# now where is it
np.nonzero((p == pnts).all(-1))[0] # we took the 2nd point remember
array([2])
# inputs for sample points and a single point
pnts
array([[38.79, 17.36],
[54.56, 80.24],
[83.56, 54.81],
[98.59, 48.87],
[98.64, 98.10],
[26.62, 1.80],
[85.05, 15.94],
[53.33, 85.95],
[ 8.25, 3.17],
[94.05, 77.85]])
p
array([83.56, 54.81]) Read once, test as appropriate or test many ps = pnts[[0, 2, 4, 6]] # take the various points
np.nonzero((ps == pnts[:, None]).all(-1))[0] # where are they, broadcasting necessary
array([0, 2, 4, 6])
ps
array([[38.79, 17.36],
[83.56, 54.81],
[98.64, 98.10],
[85.05, 15.94]])
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01-28-2026
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| Title | Kudos | Posted |
|---|---|---|
| 1 | Wednesday | |
| 1 | 3 weeks ago | |
| 1 | a week ago | |
| 1 | a week ago | |
| 1 | 2 weeks ago |