Select to view content in your preferred language

Python Labeling Help?

2960
6
Jump to solution
12-29-2015 10:58 AM
MattBrauckmann
New Contributor

I'm trying to write a python script to label multiple columns of an attribute table based on certain parameters. For example, if Benzene is over 79, I want it to be red. I've gotten that part fine, but for some reason I can't get the labels to stack, it only displays the first one the meets the if/then statement. Here's what I have so far:

def FindLabel ( [NAME], [Acetone], [Benzene], [1_3_Butadi]  ):
  if int( [Benzene] ) > 79:
    message = "<bol>" "<clr red = '255'>"+"Benzene:" + [Benzene] + "</clr>" + "</bol>"+ "\n"
    return message + "\n"
  if int( [Benzene] ) > 0:
    message = "<bol>" "<clr green = '255'>"+"Benzene:" + [Benzene] + "</clr>" + "</bol>"+ "\n"
    return message + "\n"
  if int( [Acetone] ) > 0:
    message = "<bol>" "<clr green = '255'>"+"Acetone:" + [Acetone] + "</clr>" + "</bol>" + "\n"
    return message + "\n"
  if int( [1_3_Butadi]  ) > 0:
    message = "<bol>" "<clr green = '255'>"+"1,3-Butadiene:" + [1_3_Butadi]  + "</clr>" + "</bol>"+ "\n"
    return message + "\n"

I essentially want it to display like this

Benzene: 79

Acetone: 12

1,3-Butadiene:13

I tried using:

  return "{0}\n{1}".format([Acetone], [Benzene], [1_3_Butadi])

That allowed me to stack the labels but then I lost the formatting I wanted.

0 Kudos
1 Solution

Accepted Solutions
WesMiller
Regular Contributor III

You will need to build your message. I didn't test the code below but your code should be similar.

def FindLabel ( [NAME], [Acetone], [Benzene], [1_3_Butadi]  ):
  message = ''
  if int( [Benzene] ) > 79:  
    message = message + "<bol>" "<clr red = '255'>"+"Benzene:" + [Benzene] + "</clr>" + "</bol>"+ "\n"  
    message = message + "\n"  
  if int( [Benzene] ) > 0:  
    message = message + "<bol>" "<clr green = '255'>"+"Benzene:" + [Benzene] + "</clr>" + "</bol>"+ "\n"  
    message = message + "\n"  
  if int( [Acetone] ) > 0:  
    message = message + "<bol>" "<clr green = '255'>"+"Acetone:" + [Acetone] + "</clr>" + "</bol>" + "\n"  
    message = message + "\n"  
  if int( [1_3_Butadi]  ) > 0:  
    message = message + "<bol>" "<clr green = '255'>"+"1,3-Butadiene:" + [1_3_Butadi]  + "</clr>" + "</bol>"+ "\n"  
    message = message + "\n"
  return message

View solution in original post

0 Kudos
6 Replies
WesMiller
Regular Contributor III

You will need to build your message. I didn't test the code below but your code should be similar.

def FindLabel ( [NAME], [Acetone], [Benzene], [1_3_Butadi]  ):
  message = ''
  if int( [Benzene] ) > 79:  
    message = message + "<bol>" "<clr red = '255'>"+"Benzene:" + [Benzene] + "</clr>" + "</bol>"+ "\n"  
    message = message + "\n"  
  if int( [Benzene] ) > 0:  
    message = message + "<bol>" "<clr green = '255'>"+"Benzene:" + [Benzene] + "</clr>" + "</bol>"+ "\n"  
    message = message + "\n"  
  if int( [Acetone] ) > 0:  
    message = message + "<bol>" "<clr green = '255'>"+"Acetone:" + [Acetone] + "</clr>" + "</bol>" + "\n"  
    message = message + "\n"  
  if int( [1_3_Butadi]  ) > 0:  
    message = message + "<bol>" "<clr green = '255'>"+"1,3-Butadiene:" + [1_3_Butadi]  + "</clr>" + "</bol>"+ "\n"  
    message = message + "\n"
  return message
0 Kudos
DarrenWiens2
MVP Honored Contributor

I see you've got your answer, however I think you can benefit from an 'elif' between the Benzene comparisons. Without 'elif', a value of 80 will get a red label (>79) followed by a green label (>0). With 'elif', a value of 80 will get a red label, then skip the >0 comparison:

def FindLabel ( [NAME], [Acetone], [Benzene], [1_3_Butadi]  ):  
  message = ''  
  if int( [Benzene] ) > 79:    
    message = message + "<bol>" "<clr red = '255'>"+"Benzene:" + [Benzene] + "</clr>" + "</bol>"+ "\n"    
    message = message + "\n"   
  elif int( [Benzene] ) > 0:   
    message = message + "<bol>" "<clr green = '255'>"+"Benzene:" + [Benzene] + "</clr>" + "</bol>"+ "\n"   
    message = message + "\n"  
  if int( [Acetone] ) > 0:    
    message = message + "<bol>" "<clr green = '255'>"+"Acetone:" + [Acetone] + "</clr>" + "</bol>" + "\n"    
    message = message + "\n"    
  if int( [1_3_Butadi]  ) > 0:    
    message = message + "<bol>" "<clr green = '255'>"+"1,3-Butadiene:" + [1_3_Butadi]  + "</clr>" + "</bol>"+ "\n"    
    message = message + "\n"  
  return message 

curtvprice
MVP Esteemed Contributor

My friends, here are some ideas on how to take advantage of Python's very handy string abilities...

def report(clr, lbl, val):
  return "<bol><clr {} = '255'>{}: {}</clr></bol>\n".format(
    clr, lbl, val)
def FindLabel([NAME], [Acetone], [Benzene], [1_3_Butadi]):
  message = ""
  if int([Benzene]) > 79:
    message += report("red", "Benzene", [Benzene])
  elif int([Benzene]) > 0:
    message += report("green", "Benzene", [Benzene]) 
  if [Acetone] > 0:     
    message += report("green", "Acetone", [Acetone])
  if int([1_3_Butadi]) > 0:     
    message += report("green", "1,3-Butadiene", [1_3_Butadi])
  return message 

(If you start a table, dataset, or field name with a number, you may regret it. You have been warned.)

MitchHolley1
MVP Regular Contributor

I have the same question. 

Could you give me an example of how this is executed in the Python script?

It looks as if your function is returning the message, but how exactly is that put into the feature class or shapefile you are trying to label?

Thanks for the help!

0 Kudos
DarrenWiens2
MVP Honored Contributor

Do you mean, how to build a label expression​, or something different?

0 Kudos
MitchHolley1
MVP Regular Contributor

Darren,

Yeah, that's it!  Here is a sample of the script:

Notice, the expression is in VBscript. 

temp.png

I haven't tried running this yet... but I'm 99% sure it's not going to work.

All I'm trying to do is label one feature class with stack text as noted above.

Please excuse my sloppy code, and please let me know if I need to post this as a separate post.

0 Kudos