Difference: Project Notebook vs Script Tool

[DanCrawford]

Hello.  I find that when I run a python command from my project notebook, the script runs and does what I expect it to.  When I run the same code from a toolbox script that I just created, it runs without error but doesn't do anything.

This is the notebook command:
arcpy.cartography.ConvertLabelsToGraphics(
  'Map', 20000, 'SINGLE_LAYER', 'XBA/New LTC-SUP/PofC', 'Graphics', 'DISPLAY',  
'GRAPHICS_LAYER_PER_FEATURE_LAYER', 'ONLY_PLACED', 'GroupGraphics')

This is the tool script:
import arcpy
def pofctographic():
tenure_type=arcpy.GetParameterAsText(0)
if tenure_type == "LTC-SUP":
   arcpy.AddMessage("LTC-SUP selected")
   arcpy.cartography.ConvertLabelsToGraphics(
     'Map', 20000, 'SINGLE_LAYER', 'XBA/New LTC-SUP/PofC', 'Graphics', 'DISPLAY',
     'GRAPHICS_LAYER_PER_FEATURE_LAYER', 'ONLY_PLACED', 'GroupGraphics')

if tenure_type == "CP":
  arcpy.AddMessage("CP selected")
  arcpy.cartography.ConvertLabelsToGraphics(
    'Map', 20000, 'SINGLE_LAYER', 'XBA/New CP/PofC', 'Graphics', 'DISPLAY',
    'GRAPHICS_LAYER_PER_FEATURE_LAYER', 'ONLY_PLACED', 'GroupGraphics')
pofctographic()

[CodyPatterson]

Hey @DanCrawford 

I think in the Notebook, it's setting all the project parameters automatically, but in the Toolbox, you may need to explicitly specify where everything's going, something like this:

import arcpy

def pofctographic():
    aprx = arcpy.mp.ArcGISProject("CURRENT")  # If in Pro, "CURRENT" if a .aprx file, use the path to that file
    map_obj = aprx.listMaps("Map")[0]  # Make sure 'Map' matches the name of your map

    tenure_type = arcpy.GetParameterAsText(0)
    if tenure_type == "LTC-SUP":
        arcpy.AddMessage("LTC-SUP selected")
        arcpy.cartography.ConvertLabelsToGraphics(
            map_obj, 20000, 'SINGLE_LAYER', 'XBA/New LTC-SUP/PofC', 'Graphics', 'DISPLAY',
            'GRAPHICS_LAYER_PER_FEATURE_LAYER', 'ONLY_PLACED', 'GroupGraphics')
    elif tenure_type == "CP":
        arcpy.AddMessage("CP selected")
        arcpy.cartography.ConvertLabelsToGraphics(
            map_obj, 20000, 'SINGLE_LAYER', 'XBA/New CP/PofC', 'Graphics', 'DISPLAY',
            'GRAPHICS_LAYER_PER_FEATURE_LAYER', 'ONLY_PLACED', 'GroupGraphics')

pofctographic()

Let me know if that works!

Cody

[DanCrawford]

Thanks!  I'm off work until Tuesday but will let you know.

[DanCrawford]

Sadly, adding those parameters has no effect.

[DanCrawford]

Same thing happens if I run it as a model.  Manual model works fine, run from the toolbox does nothing.

[AlfredBaldenweck]

I don't have much constructive to add except for I'm currently wrapping up a support case where notebooks/python window work for the code but an ATBX or a PYT also run and do nothing with the exact same code while calling a Geoprocessing Service. 

All this to say, it isn't unheard of.

[DavidSolari]

I swapped out the toolbox parameter for a feature layer input and got it down to this 2-line reproduction:

import arcpy
arcpy.cartography.ConvertLabelsToGraphics(
    arcpy.mp.ArcGISProject("CURRENT").activeMap,
    20000,
    'SINGLE_LAYER',
    arcpy.GetParameterAsText(0),
    'Graphics',
    'MAXOF',
    'GRAPHICS_LAYER_PER_FEATURE_LAYER',
    'ONLY_PLACED',
    'GroupGraphics'
)

I get the same issue as you in Pro 3.4.0, no changes are made to the map. I think the next move is to contact your support team to see if they can replicate it, hopefully this leads to a bug fix or a workaround.

[DanCrawford]

Thanks.  I have opened a ticket with ESRI.  I'll update this post if/when a solution is provided.

[DanCrawford · Accepted solution]

Dylan from ESRI Canada has provided this solution:
As a workaround, you can assign the result of the arcpy.cartography.ConvertLabelsToGraphics function to a variable, then add the first element of this variable (which will be the group layer) to the map object as follows:

import arcpy
arpx = arcpy.mp.ArcGISProject("CURRENT")
map_obj = arpx.listMaps("Map")[0]
glayer = arcpy.cartography.ConvertLabelsToGraphics(map_obj, 2000, 'SINGLE_LAYER', 'XBA/PofC')
map_obj.addLayer(glayer[0])

 Thank-you Dylan!