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Custom script tool parameters will not accept decimals

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10-18-2021 12:33 PM
JaredPilbeam2
MVP Regular Contributor

b1.png

I have a script tool that sets a layer's break values and their labels. The user will also need to enter decimals as values. I can't seem to get the tool to do that. Here I have the break values set to accept a Long data type. I've also tried a double, and a string.

The break values entered into the tool are forced to be integers in the script.

 

#class break values
classbreakvalues = sys.argv[1] #break value parameter entered here
breakvalues_list = classbreakvalues.split(";")
new_breakvalues_list = []
for brkvalues in breakvalues_list:
    newbreak = int(brkvalues) # integer value
    new_breakvalues_list.append(newbreak)
classBreakValues = new_breakvalues_list

 

If I run the following, the tool won't accept a decimal value.

b2.png

I get this error, which I understand to mean you can't have an string as an integer. But I don't see how that could be.

 

ValueError: invalid literal for int() with base 10: '70.5'

 

 

 

1 Solution

Accepted Solutions
by Anonymous User
Not applicable

The int type can't have decimals so you need to use a float conversion if you want to persist the decimal values.

 

newbreak = float(brkvalues) # integer value

 

 

You can cast to float first then int, but it will truncate your number.

val = int(float(brkvalues))

 

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8 Replies
DanPatterson
MVP Esteemed Contributor
classbreakvalues.split(";")

suggests that the values are being returned as a semicolon delimited string.  If that is the cast them to a float when you get them.

vals = "40;45;70.5;100"

v = vals.split(";")

v0 = [float(i) for i in v]

v
['40', '45', '70.5', '100']

v0
[40.0, 45.0, 70.5, 100.0]

... sort of retired...
by Anonymous User
Not applicable

The int type can't have decimals so you need to use a float conversion if you want to persist the decimal values.

 

newbreak = float(brkvalues) # integer value

 

 

You can cast to float first then int, but it will truncate your number.

val = int(float(brkvalues))

 

JaredPilbeam2
MVP Regular Contributor

 

 

 

newbreak = [float(i) for i in brkvalues]

 

 

@DanPattersonIf I use that it gives me: TypeError: int() argument must be a string, a bytes-like object or a number, not 'list'.

 

@Anonymous UserI used float(brkvalues) and set the tool Data Type to Double. The tool ran with no error, but the value I set to a decimal was not changed in the symbology. And yes, I've noticed newbreak = int(float(brkvalues)) doesn't show the decimal places in the symbology either.

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DanPatterson
MVP Esteemed Contributor

you have to int a float not a string, hence int(float("1.1")), but int("1") is ok (refer to type conversion docs in python)


... sort of retired...
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JaredPilbeam2
MVP Regular Contributor

Using newbreak = float(brkvalues) also does something with the highest value in a particular field. I set the last upper break value to be 100 in the tool parameters before I ran it. But, for some reason its grabbing the highest value in a particular layer's table and setting it as the last upper value in the symbology. Here, for example, 69.57 is the highest value in the % Vaccinated - 14-16 field. It ignores my label and it shows a decimal?

JaredPilbeam2_0-1634656325481.png

 

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JaredPilbeam2
MVP Regular Contributor

JaredPilbeam2_0-1634754762147.png

 

All three of the following arrangements in the code are successful when running them from the script tool. But, not one of them change the break value to a decimal in the layer's symbology. This leads me to believe something is up with the tool.

 

#Results in neither decimal in layer symbology nor print statement
for brkvalues in breakvalues_list:
    newbreak = int(float(brkvalues))
    arcpy.AddMessage(f'newbreak: {newbreak}')

#prints these values
#break value: 40
#break value: 45
#break value: 60
#break value: 100

#No decimal in layer symbology, but decimal in print statement
for brkvalues in breakvalues_list:
    newbreak = float(brkvalues)
    arcpy.AddMessage(f'break value: {newbreak}')

#prints these values
#break value: 40
#break value: 45
#break value: 60.9
#break value: 100

#No decimal in layer symbology, but decimal in print statement
from decimal import Decimal
for brkvalues in breakvalues_list:
    newbreak = Decimal(brkvalues)
    arcpy.AddMessage(f'break value: {newbreak}')

#prints these values
#break value: 40
#break value: 45
#break value: 60.9
#break value: 100

 

 

 

 

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JaredPilbeam2
MVP Regular Contributor

OK, I was too focused on one part of the script. The snippet I had posted above was the section of code that takes the users input and puts it into a variable. Then there is the other part of the script the assigns that input to the upperBound element of the symbology. This is what I needed to convert to a float! Thanks for your answers.

import arcpy, sys

aprx = arcpy.mp.ArcGISProject('CURRENT')

#make sure fields in list are in same order as maps in project
fields =  ['VaccPercentageTotPop', 'VaccPercentage11to14', 'VaccPercentage0to18', 'VaccPercentage12to18',  
           'VaccPercentage14to16', 'VaccPercentage16to18', 'VaccPercentage19to64', 'VaccPercentage65Plus']

c = 0 #use counter to give a number to each map in for loop
for map in aprx.listMaps():
    arcpy.AddMessage(f'--- map: {map.name} ---')
    layers = map.listLayers()
    for layer in layers:
        arcpy.AddMessage(f'layer: {layer.name}')
        sym = layer.symbology   
        #Reset renderer 
        sym.updateRenderer('SimpleRenderer')
        sym.updateRenderer('GraduatedColorsRenderer')

        if hasattr(sym, 'renderer') and layer.name.startswith('BaseLayer'):
            Renderer = sym.renderer
            Renderer.classificationField = fields[c]
            #class break values
            classbreakvalues = arcpy.GetParameterAsText(0)
            breakvalues_list = classbreakvalues.split(";")
            new_breakvalues_list = []
            for brkvalues in breakvalues_list:
                newbreak = brkvalues
                arcpy.AddMessage(f'break value: {newbreak}')
                new_breakvalues_list.append(newbreak)
            classBreakValues = new_breakvalues_list
            #class break labels
            classbreaklabels = arcpy.GetParameterAsText(1)
            breaklabels_list = classbreaklabels.split(";")
            classBreakLabels = breaklabels_list

            # Run the Renderer.breakCount function to use the classBreakValues 
            # array parameters as the values, and create a counter.
            Renderer.breakCount = len(classBreakValues)

            i = 0 
            for brk in Renderer.classBreaks:
                brk.upperBound = float(classBreakValues[i]) #<-- Convert this to float
                arcpy.AddMessage(f'upper bound in symbology: {brk.upperBound}')
                brk.label = classBreakLabels[i]
                i+=1

                layer.symbology = sym
    c+=1

 

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JaredPilbeam2
MVP Regular Contributor

Interestingly, all I had to do was change arcpy.GetParameterAsText() to arcpy.GetParameter(). Then I didn't even have to bother with later changing the value to a float.