Con function on Zonal Geometry Raster

09-28-2013 10:40 AM
New Contributor
I have a Zonal Geometry output raster that I would like to perform the Con tool/function on.  When I try I get this error:

Executing (Con): Con "C:\Users\Agent\Desktop\FOR2286\Spatial Analysis and Modeling\Reclassify\Data\Woodlot II\UNB Woodlot.mdb\ZonalGe_Regi1" 1 "C:\Users\Agent\Desktop\FOR2286\Spatial Analysis and Modeling\Reclassify\Data\Woodlot II\UNB Woodlot.mdb\SQHabitat" # ""Value" >=50000"
Start Time: Sat Sep 28 14:28:24 2013
ERROR 999999: Error executing function.
(DAO.Recordset) No current record.
ERROR 010416: Error in setting raster table filter for C:\Users\Agent\Desktop\FOR2286\Spatial Analysis and Modeling\Reclassify\Data\Woodlot II\UNB Woodlot.mdb\ZonalGe_Regi1.
ERROR 010213: Error in reading raster Layer_1.
ERROR 010325: Run-time error - ***.
ERROR 010067: Error in executing grid expression.
Failed to execute (Con).
Failed at Sat Sep 28 14:28:24 2013 (Elapsed Time: 0.00 seconds)

I am working in ArcMap 10.1, windows 7 64 bit pro.  The Zonal Geometry raster is 32 bit floating.  It seems like any Con function/tool cannot read the values in the zonal raster. 

The workflow is originally from a simple model I made: Raster calculator output raster into Region Group, Region Group raster into Zonal Geometry, Zonal Geometry raster output into Con tool or raster calculator for areas >=50000 meters square and I get this error.

I have had the zonal raster in personal and file geodatabases, on its own in a folder, I've converted the raster to 16/8 bit, taken out spaces in paths and had the same error.

In the above error I've typed the expression as the sql builder does not let me choose/see a "value" field.

Any suggestions?

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1 Reply
Regular Contributor III
Some suggestions:

1. Make sure the zone raster is interger-based and has a raster attribute table built for it
2. Use FGDB or GRID format rasters (don't use a personal geodatabase, unless there is a good reason)
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