Polygon with given length and width JLF

10-11-2017 01:45 PM
New Contributor

How to create polygon (Projected NAD83) with specific length and width, but no X,Y points*

Tags (1)
0 Kudos
2 Replies
MVP Emeritus
  • Projected into what? 
  • NAD83 is a datum not a projection
  • It can be done if you don't care where it is.

Perhaps you have other details that you could share.

Esri Esteemed Contributor

I totally agree with Dan.

It can be done, but a little bit more info would be appreciated. To create a rectangle you will need coordinates. You can create them randomly but you will still need some range of valid values. See below a sample script that will create a number of rectangles. In this case I took the projected coordinate system with NAD 1983 as datum and defined an extent for values values for xmin and ymin of the rectangles to be created:

def main():
    import arcpy
    import random
    arcpy.env.overwriteOutput = True

    # some settings
    fc_out = r'C:\GeoNet\RandomRectangle\test2.shp'
    width = 10000
    height = 5000
    xy_extent = arcpy.Extent(2048900, 549400, 2094700, 573600)
    number_of_rectangles = 25

    # NAD_1983_2011_StatePlane_California_V_FIPS_0405
    sr_pcs = arcpy.SpatialReference(103001)

    feats = []
    for i in range(number_of_rectangles):
        # get a random xmin and ymin of the rectangle
        xmin = random.randrange(xy_extent.XMin, xy_extent.XMax)
        ymin =random.randrange(xy_extent.YMin, xy_extent.YMax)

        # create the rectangle
        pnts = [[xmin, ymin],
                [xmin, ymin + height],
                [xmin + width, ymin + height],
                [xmin + width, ymin],
                [xmin, ymin]]

        polygon = arcpy.Polygon(arcpy.Array([arcpy.Point(*pnt) for pnt in pnts]), sr_pcs)

    # write the rectangle to the output fc
    arcpy.CopyFeatures_management(feats, fc_out)

if __name__ == '__main__':

And the result:

Could you elaborate a little more on what you are trying to achieve?