How to conditionally display image in popup

Question

Hello! I am trying to create a popup that displays an image from the URL in the Picture field of my feature layer. However, some features do not have a picture URL and are null and in those cases I would like it to display nothing, instead of the broken image icon or the outline of where the image should be.

I have been messing around with different Arcade expressions and HTML tags but cannot seem to figure it out.

Is there any way to do this?

jcarlson · Answer

You should be able to do this with an Arcade popup element. var photo_viz = Iif(IsEmpty($feature['photo_url']), 'none', '') return { type : 'text', text : `` }