The links seem fine from here as well. Kevin, Let me know which aren't working for you and I will investigate!

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soooo I randomly clicked one

Spatial Statistics: Simple Ways to Do More with Your Data (2015 Video, PDF)

pdf

**This shared file or folder has been removed.****Please check the URL or contact the owner, as the shared link may have changed. You can also visit one of the following pages for help:**and it is dead... So assuming that the rest were, I flag

I have a knack for picking them.... hope you folks checked all the rest

Timothy Hales link still doesn't work for me. Tested in Chrome and Firefox. Do other people get this to work?

link -- Our Chapter in the Handbook of Applied Spatial Analysis

It just says "Disallowed Key Characters." in both browsers.

If I can help somehow I will be glad to test anything.

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I'm going to look into the blog redirect issue for sure... In the meantime, I am happy to send you the chapter! Please email me at jdacosta@esri.com on where to send this. I don't think can upload it here on geonet (although I may be wrong) and I don't see an email in your profile.

-Jenora

- 2 people found this helpful
Here is the correct link to the blog - Check out our chapter on Spatial Statistics in ArcGIS in the Handbook of Applied Spatial Analysis | ArcGIS Blog

Dan Patterson Jenora D'Acosta thank you! Can email to me my contact info is SAGIS.org or I will send you a PM if you follow me (I believe that is how it works? I followed you Jenora)

And, is this the most up to date book on Spatial Analyst? http://downloads2.esri.com/support/documentation/ao_/Using_ArcGIS_Spatial_Analyst.pdf

One question I'm trying to ascertain the answer to is how to calculate amount of features per cell from point density. It produces 'magnitude'. I just want to know how many trees per cell this actually means. Any explanation thus far I have found I do not understand. I understand if it's circular the neighborhood area will be given by pi*r2. However the examples in Ch 3 in David Allen's Spatial Analyst WorkBook (page 130) I just can't figure out simply calculating the number of trees per cell as in the example, instead of this 'density' or 'magnitude' that is a much larger number, the thousands, than what should be a few trees per cell at most (6meter). In fact it wouldn't it make more sense to just give this value anyhow? I also am a little hazy on the following the point of the 'cell size' guidance of 10 to 100 cells, in the accompanying Esri Guide to GIS Volume 1 in the Density Chapter. I have looked a good bit and not found much online. Thank you to anyone with any comments.

Aaand update: I'm working through it. I realized I needed to search in Spatial Analyst forum. Threads like these appear relevant. https://community.esri.com/message/242698?commentID=242698#comment-242698 How exactly does the Point Density tool calculate cell values in SA? it is per neighborhood area with that cell as center, I will test and confirm tomorrow with the text's examples and calc by hand to ensure I understand it.

Update 2: it appears to pan out. I backcalculated feature count at a cell (well, for the neighborhood that is centered upon the cell, as these threads above explain).If I understand correctly the cell value is the magnitude, i.e. value for the WHOLE neighborhood, with the particular pixel (cell) in question, when you look at a single cell’s value. To back-calculate actual number of features, multiple the area by the cell value, keeping area in map units with cell size of one. (circular neighborhood area A = π ×

*r*) Example: if two points overlap, value in between should be 2. Value within neighborhood not overlapping should be 1. Value outside neighborhood should be zero. 64*0.001592 = 2 (Example from text but with neighborhood of 20, cell size 1, area in map units squared, cell magnitude of 0.001592, and generating a value of 2.0 in calculation) I see now that density surface is not an interpolation of predicted values, but of the^{2}**count**of features in an entire neighborhood, centered upon each cell. The scalar of square area unit is simply what would need to be divided by so I keep it the same by using Map unit sq. Is this all correct?I have found calculations now to pan out as above, but the example using 'trees' in Texas in the Workbook appears to violate the assumption of random samples!

How should I interpret the output of density tools? | ArcGIS Blog

Lauren Bennett Jenora D'Acosta perhaps a flag will provide some answers to the redirect