I have an incident Point feature class. I calculate the Mean Center.
Now I would like to calculate:
25% of the incidents compared to the Mean Center Then draw a circle to cover the 25%.
50% incidents compared to the Mean Center Then draw a circle to cover the 50%
What percentage of the incidents are closer to the xx office compared to yy office.
Any Idea or Model or Python script.
Thanks
Solved! Go to Solution.
Standard Distance ... How it works... is what you want to use
Standard Distance ... How it works... is what you want to use
Thank you Dan, Not exactly what I want, I am not Measuring the compactness of a distribution this way. I am looking to draw some thing like buffers according to the Percentage I mentioned from the mean Center-
besides need to answer the question of : What percentage of the incidents are closer to the xx office compared to yy office ( I have 2 offices, point feature.
Thanks
Husham... that is what it will do... given points, the standard distance represents the distance (a circle radius) that encompasses a certain proportion of the distribution. a 1 std deviation in both X and Y (check the formula for details) would suggest that 68% of the points would fall within that distance.. So for 50% you want about 0.6745 std distances. The tool will actually create circles using defaults. Otherwise you can use the radius to make your own buffers.
Thanks
Will try that and get back to you.