# Trend Analysis Through Time Series of Raster Data

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07-27-2017 11:14 AM Occasional Contributor III

Hi All,

I have total 13 raster files for different years (2001 - 2013). All data are in tiff format and same spatial extent (row and column). I am trying to perform regression line slope/trend analysis between each grid points for 13 raster data sets. I have tried in ArcGIS raster calculator but I won't run the task due to complexity.

The outcome would measure the net change between pixels through my time series data.

So my question is, can it be performed using raster calculator or ArcPy Script?  For such type of statistical analysis using ArcGIS, really I am facing one of the big limitation with ArcGIS.

Using excel, it can be calculated using SLOPE command where X (Time) and Y (value) has been used. But for creating a Spatial map of Slope/trend analysis, we need to perform using raster data.

The download link is given below for Sample data sets (Due to size limit, I could not attach the data with here )

Data Link: Dropbox - Water_Use_Efficiency.zip

Please share your experience.

Thanks in advance.

1 Solution

Accepted Solutions by Esri Esteemed Contributor
31 Replies Occasional Contributor III

Xander Bakker Patterson‌ , A request to you peoples, We need your kind cooperation to solve the issue.  Since long i am trying but not solved yet. Thanks by Esri Esteemed Contributor

Hishouvik jha ,

Recently I needed to detect strange behavior in monthly consumption by water consumers. I created a data structure that had the 12 months of data for each client as attributes of a point file. The code below is a snippet that takes a list of data (this could be the 13 values for each pixel in your case) and calculates a regression line based on the data.

The slope will tell you if there is an increase or decrease in the range of data. In my case to detect this abnormal behavior I determined the average value, and the mean distance for each value to the regression line divided by mean value. The higher the value the less constant the consumption.

I think you could use this code (or parts) to create the numpy arrays for each raster and loop through the individual pixels (create a list of values for the 13 years you have for each pixel, do the calculation and fill an output array to write the result of the analysis to an output raster. I'm pretty sure there must be an easier way to do this, or even a standard way to calculate this on a time series of data. I will investigate a little more and let you know.

``from numpy import arange,array,ones,linalgdef main():    # some test input data (lists of 12 elements with possible NoData)    lst_data = [[2.0, None, None, None, None, 1.0, 4.0, 6.0, 5.0, 7.0, 9.0, 9.0],           [None, None, None, None, None, None, None, None, None, None, 15.0, 16.0],           [14.0, 11.0, 25.0, 4.0, 4.0, 4.0, 3.0, 4.0, 2.0, 3.0, 4.0, 4.0],           [7.0, 9.0, 7.0, 3.0, 2.0, 2.0, None, 13.0, 5.0, 60.0, 25.0, 25.0],           [1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0, 11.0, 12.0],           [1.0, 2.0, 1.0, 2.0, 1.0, 2.0, 1.0, 2.0, 1.0, 2.0, 1.0, 2.0],           [11.0, 12.0, 11.0, 12.0, 11.0, 12.0, 11.0, 12.0, 11.0, 12.0, 11.0, 12.0]]    # loop through input data    for lst in lst_data:        print "\ndata:", lst        # calculate regression line: y = ax + b        a, b, sum_abs_dif, avg_abs_dif = RegressionLine(lst)        if not a is None:            cons_prom = getAvg(lst)            print " - mean value:", cons_prom            print " - slope     (a):", a            print " - intercept (b):", b            print " - total distance from regression line:", sum_abs_dif            print " - mean distance from regression line :", avg_abs_dif            # print a, b, sum_abs_dif, avg_abs_dif            print " - score:", avg_abs_dif / cons_prom        else:            print " - Insufficient data"def RegressionLine(lst):    from numpy import arange, array, ones, linalg    months = range(1, 13)    lst_x = []    lst_y = []    cnt = 0    for a in lst:        if not a is None:            lst_x.append(months[cnt])            lst_y.append(a)        cnt += 1    cnt_elem = len(lst_x)    if cnt_elem >= 2:        A = array([ lst_x, ones(len(lst_x))])        # linearly generated sequence        w = linalg.lstsq(A.T, lst_y)        # obtaining the parameters of the regression line        a = w  # slope        b = w  # offset        # calculate acumulated abs difference from trend line        zip_lst = zip(lst_x, lst_y)        sum_abs_dif = 0        for xy in zip_lst:            x = xy            y = xy            calc = x * a + b            abs_dif = abs(y - calc)            sum_abs_dif += abs_dif        avg_abs_dif = sum_abs_dif / cnt_elem        return a, b, sum_abs_dif, avg_abs_dif    else:        return None, None, None, Nonedef getAvg(lst):    corr_lst = [a for a in lst if not a is None]    cnt = len(corr_lst)    if cnt == 0:        return None    else:        return sum(corr_lst) / float(cnt)if __name__ == '__main__':    main()‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍``

Results:

``data: [2.0, None, None, None, None, 1.0, 4.0, 6.0, 5.0, 7.0, 9.0, 9.0] - mean value: 5.375 - slope     (a): 0.738095238095 - intercept (b): -0.529761904762 - total distance from regression line: 9.29761904762 - mean distance from regression line : 1.16220238095 - score: 0.216223698782data: [None, None, None, None, None, None, None, None, None, None, 15.0, 16.0] - mean value: 15.5 - slope     (a): 1.0 - intercept (b): 4.0 - total distance from regression line: 3.5527136788e-15 - mean distance from regression line : 1.7763568394e-15 - score: 1.14603667058e-16data: [14.0, 11.0, 25.0, 4.0, 4.0, 4.0, 3.0, 4.0, 2.0, 3.0, 4.0, 4.0] - mean value: 6.83333333333 - slope     (a): -1.18181818182 - intercept (b): 14.5151515152 - total distance from regression line: 42.303030303 - mean distance from regression line : 3.52525252525 - score: 0.515890613452data: [7.0, 9.0, 7.0, 3.0, 2.0, 2.0, None, 13.0, 5.0, 60.0, 25.0, 25.0] - mean value: 14.3636363636 - slope     (a): 2.69171974522 - intercept (b): -3.0101910828 - total distance from regression line: 103.946496815 - mean distance from regression line : 9.44968152866 - score: 0.65788922035data: [1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0, 11.0, 12.0] - mean value: 6.5 - slope     (a): 1.0 - intercept (b): -1.46316339947e-15 - total distance from regression line: 3.17523785043e-14 - mean distance from regression line : 2.64603154202e-15 - score: 4.07081775696e-16data: [1.0, 2.0, 1.0, 2.0, 1.0, 2.0, 1.0, 2.0, 1.0, 2.0, 1.0, 2.0] - mean value: 1.5 - slope     (a): 0.020979020979 - intercept (b): 1.36363636364 - total distance from regression line: 5.87412587413 - mean distance from regression line : 0.48951048951 - score: 0.32634032634data: [11.0, 12.0, 11.0, 12.0, 11.0, 12.0, 11.0, 12.0, 11.0, 12.0, 11.0, 12.0] - mean value: 11.5 - slope     (a): 0.020979020979 - intercept (b): 11.3636363636 - total distance from regression line: 5.87412587413 - mean distance from regression line : 0.48951048951 - score: 0.042566129522‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍`` by Esri Esteemed Contributor Occasional Contributor III

Hi Xander Bakker‌, Thank you.

The script is quite interesting. in above script, there are seven client's data has been used for the analysis. Instead of using a numeric value which you assigned as an input data, it can be possible to assign raster file or ASC file in there? If is it possible to use raster or ASC file as an input data then output also can be written in raster format. (Plz give your opinion also)

Somewhere I have read that if we stack all the year's data and make it a single raster. Might be it will help us to perform a loop on all pixels (number of the pixels at same grid point for all years, so in my case at the same grid point, the number of pixels is 13) at same grid point for the raster based statistical analysis such as trend, correlation etc.

basically, Since long the geospatial research communities are also looking for the same analysis on Python or ArcGIS raster calculator platform, as following

1) Raster based Trend Analysis through time series data.

2) Raster based correlation analysis between two variables. Just assume the correlation analysis between Temperature and precipitation raster data and output also be in raster format.

If the above issues can be solved on Python platform so it would be a very good news for all researchers who are looking for the solution since long.

The tool which you suggested, It is very helpful and the number of functions is inbuilt with the tool but the only issue is, it is only functioning on ArcGIS 10.1 version. It is not compatible with the later version of ArcGIS 10.1 and taking too long time for the analysis. However, I am going through with that tool. In addition, I am trying to further explore the script which you provided.

It is our kind request behalf of the geospatial research community, India, please show a path to overcome the issues. If you need the sample data, I can provide you some datasets for further investigation on the matter.

Once again thank you very much for your cooperation.

With warm regards

Shouvik Jha by Esri Esteemed Contributor

Hi shouvik jha ,

For your first question, is it possible to connect to a datasource, the answer is yes. In my case the data was available as point data and the 12 values as 12 fields for each feature. I read them into a list of values and process the results and write the output statistic values to additional field in the point feature class.

In your case you have a list of 13 raster where each raster aligns with the other raster and the number of rows and columns match. You will have to loop through each pixel location in a numpy array that was created from converting the each raster to a numpy, and for each pixel location you will read the 13 values out (from the 13 numpy arrays), construct the list, perform the analysis and populate a new numpy array as the output result.

It would be interesting to have access to the 13 rasters to see what can be done. So if you can share them, please attach them at the thread.

You could also explore the How Band Collection Statistics works—Help | ArcGIS Desktop tool, although this will not create a raster as a result, but a report using the pixels in a diagonal of the bands (you will need to check the "compute covariance and correlation matrices" option). Occasional Contributor III

Hi Xander Bakker‌, Thank you.

I have attached the Dropbox link at the thread for accessing the data. Due to the size limit, I could not attach the data with here, however, you can download the data by that link and please have a look. by MVP Esteemed Contributor

You shouldn't have to cycle through the cells of a stacked raster .... consider

``# ---- create a 'raster' consisting of 4 rows and 5 columns with 12 #      months of data... ie. 12 months x 4 rows x 5 columnsa = np.arange(12*4*5).reshape(12, 4, 5)a  # ---- the first montharray([[ 0,  1,  2,  3,  4],       [ 5,  6,  7,  8,  9],       [10, 11, 12, 13, 14],       [15, 16, 17, 18, 19]])a[-1] # ---- the last month ..... you get the drift I hopearray([[220, 221, 222, 223, 224],       [225, 226, 227, 228, 229],       [230, 231, 232, 233, 234],       [235, 236, 237, 238, 239]])top_left_12months = a[:, 0, 0]  # --- let's get the top-left cell's dataarray([  0,  20,  40, ..., 180, 200, 220])  # ---- makes sense doesn't it?np.mean(top_left_12months)  # ---- the 12 month mean for the top left cell110.0np.mean(a, axis=0)  # ---- Since I am lazy, I will get every cell's averagearray([[ 110.00,  111.00,  112.00,  113.00,  114.00],       [ 115.00,  116.00,  117.00,  118.00,  119.00],       [ 120.00,  121.00,  122.00,  123.00,  124.00],       [ 125.00,  126.00,  127.00,  128.00,  129.00]])# ---- Notice the top left cell value is correct#‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍``

The point being,... once you snag the data you can do anything you want to it.  In the above example, I simply used a builtin function to calculate the mean... that doesn't mean that I am restricted to using builtin functions.  The possibilities are endless since calculations can be 'vectorized' in any dimension... in this case, by row, by column or by depth/band/month/whatever is the 3rd dimension.

PS  handling nodata values is trivial when working with arrays... in fact, many are builtin... instead of np.mean... there is amazingly ... np.nanmean() Occasional Contributor III

Thanks, Dan_Patterson‌, I am trying to further explore the script. by Esri Esteemed Contributor

See below an example which I created from the slope of the regression line based on the 13 values. This means that if the values increment in time they will have a positive slope (red) and in case of a decreasing regression line a negative slope (green): The code used to create this raster is:

``#-------------------------------------------------------------------------------# Name:        stats_numpy_series.py# Purpose:## Author:      Xander## Created:     30-07-2017#-------------------------------------------------------------------------------def main():    print "load modules..."    import arcpy    import numpy as np    # template = r'C:\GeoNet\LoopMultiFolderCalcMeanSameFolder\Test_Data\2004A\{0}162004.tif'    template = r'C:\GeoNet\WUE\r{0}_WUE.TIF'    nodata = -3.4028235e+38    out_ras = r'C:\GeoNet\WUE\WUE_slope.tif'    print "create numpy list..."    lst_np_ras = []    for i in range(1, 14):        ras_path = template.format("%03d" % (i,))        print " - ", ras_path        ras_np = arcpy.RasterToNumPyArray(ras_path)        lst_np_ras.append(ras_np)    print "read props numpy raster..."    ras_np = lst_np_ras    rows = ras_np.shape    cols = ras_np.shape    print "create output numpy array..."    ras_path = template.format("%03d" % (1,))    raster = arcpy.Raster(ras_path)    ras_np_res = np.ndarray((rows, cols)) # np.ndarray((raster.height, raster.width))    print "loop through pixels..."    pix_cnt = 0    for row in range(rows):        for col in range(cols):            pix_cnt += 1            if pix_cnt % 10000 == 0:                print "row:", row, "  col:", col, "  pixel:", pix_cnt            lst_vals = []            for ras_np in lst_np_ras:                lst_vals.append(ras_np[row, col])            lst_vals = ReplaceNoData(lst_vals, nodata)            # perform calculation on list            a, b, sum_abs_dif, avg_abs_dif, cnt_elem = RegressionLine(lst_vals)            if cnt_elem > 1:                val = a##                print " - ", lst_vals##                print " - slope     (a):", a##                print " - intercept (b):", b##                print " - total distance from regression line:", sum_abs_dif##                print " - mean distance from regression line :", avg_abs_dif            else:                val = nodata            try:                ras_np_res[row, col] = val            except:                print "err"    pnt = arcpy.Point(raster.extent.XMin, raster.extent.YMin)    xcellsize = raster.meanCellWidth    ycellsize = raster.meanCellHeight    ras_res = arcpy.NumPyArrayToRaster(ras_np_res, lower_left_corner=pnt, x_cell_size=xcellsize,                             y_cell_size=ycellsize, value_to_nodata=nodata)    ras_res.save(out_ras)    arcpy.DefineProjection_management(in_dataset=out_ras, coor_system="GEOGCS['GCS_WGS_1984',DATUM['D_WGS_1984',SPHEROID['WGS_1984',6378137.0,298.257223563]],PRIMEM['Greenwich',0.0],UNIT['Degree',0.0174532925199433]]")def ReplaceNoData(lst, nodata):    res = []    for a in lst:        if a < nodata / 2.0:            res.append(None)        else:            res.append(a)    return resdef RegressionLine(lst):    from numpy import arange, array, ones, linalg    months = range(1, 14)    lst_x = []    lst_y = []    cnt = 0    for a in lst:        if not a is None:            lst_x.append(months[cnt])            lst_y.append(a)        cnt += 1    cnt_elem = len(lst_x)    if cnt_elem >= 2:        A = array([ lst_x, ones(len(lst_x))])        # linearly generated sequence        w = linalg.lstsq(A.T, lst_y)        # obtaining the parameters of the regression line        a = w  # slope        b = w  # offset        # calculate acumulated abs difference from trend line        zip_lst = zip(lst_x, lst_y)        sum_abs_dif = 0        for xy in zip_lst:            x = xy            y = xy            calc = x * a + b            abs_dif = abs(y - calc)            sum_abs_dif += abs_dif        avg_abs_dif = sum_abs_dif / cnt_elem        return a, b, sum_abs_dif, avg_abs_dif, cnt_elem    else:        return None, None, None, None, Noneif __name__ == '__main__':    main()‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍``

I have attached the raster for you to examine.

Kind regards, Xander 