Hi,
am facing a problem exporting features to KMZ please if any one could help .
well i am exporting a huge number of features almost "1800" so am using export layer to kml in the batch mode .
so here's the problems the tool just truncated the names of the features but if i entered the full name by typing , it exports it pretty will !
so how can i export the features with there names there must be a way to do it beside typing name for each ! . right ?
See this help page for how to use the Check Values button to generate output file names, based on inputs:
thank you Darren ,
i see the link you sent but it doesn't work for my case here .
the out buts are based in the inputs but its not the exact same , in my case when i Check Values button to validate the output ,
the names truncated to a smaller names !
i need it to be the same as the input without the need to do it one by one .
i need the arc to automatically generates output but with the exact names given in the input .
is that possible ?!
thank you .
Probably not possible in batch processing. Possibly possible in model builder using an iterator. Definitely possible using python.
Ahmed,
I have a python script that searches through a directory/geodatabase and creates KMZ files.
What it does is create an replica of the input workspace(folder/geodatabase) and produce .kmz files.
Not sure how familiar you are with python but I will copy my code here:
def export_to_kml(input_workspace, output_workspace): """ This function extracts the feature classes from a geodatabase and converts them to .kmz files directory structure is maintained by folders being created based on the feature dataset. input_workspace ==> Path to a: Geodatabase, Folder which contains Feature Classes or Shapefiles. (EX: 'H:\GIS DATA\Counties.gdb') output_workspace ==> Path to the location you want the .kmz files to go. (EX: 'H:\GIS DATA') """ # Searches through all sub-directories within the input workspace import os for dirpath, dirnames, filenames in arcpy.da.Walk(input_workspace): for dirname in dirnames: # vars dir_path = os.path.join(dirpath, dirname) arcpy.env.workspace = dir_path fcs = arcpy.ListFeatureClasses() print("Processing Feature Dataset/Folder:{0}\nFeature Classes/Shapefiles:{1}\n".format(dir_path, fcs)) arcpy.CreateFolder_management(output_workspace, dirname) suboutput = os.path.join(output_workspace, dirname) count = 0 for fc in fcs: print("Converting: {0}".format(fc)) count = count + 1 layer = 'layer' + fc out_kmz_file = os.path.join(suboutput, fc + '.kmz') layer_output_scale = 0 is_composite = 'false' boundary_box_extent = '#' image_size = 1024 dpi = 300 zvalue = 'CLAMPED_TO_GROUND' arcpy.MakeFeatureLayer_management(fc, layer) # Creates a layer to convert to the .kmz arcpy.LayerToKML_conversion(layer, out_kmz_file, layer_output_scale, is_composite, boundary_box_extent, image_size, dpi, zvalue) print("{0} complete\n".format(count))
The way that you can run this is by opening the python window and copy and pasting this script(attched a .txt to make it easy) into the command line.
from there you can type out:
>>>export_to_kml('H:\input\geodatabase.gdb', 'C:\Users\XXXXX\Desktop\kmz') # first value is your input folder/gdb second value is your output location
Let me know if you need any help with it
Also this will create the kmz file with the orginal name of your shapefile/feature class