How to find the URL for my REST API?

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a week ago
New Contributor

I am new to ARC GIS but have been tasked to get data about a map and grab the layers / tables / data behind those labels.

I have created a new Application and obtained the token. Where I am getting confused is I cannot figure out where the URL I need to query for the end point. For example:

https://services.arcgis.com/<abcdef>/arcgis/rest/services/<layer>/FeatureServer/0/query

Where do I find abcdef? Also do I always use services.arcgis.com or do I use my companies url which is <hidden>.maps.arcgis.com.

 

The API Documentation does not explain this at all unless I am missing something. They reference it but do not show how to actually get that information. I tried to reach https://<hidden>.maps.arcgis.com/arcgis/rest/services and I am getting a 404 not found error.

I believe if I am able to find how to get to my rest api I can take it from there.

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Esri Contributor

Hi @AmyWoods2 ,

 

What you are looking for might be not exactly documented. However, if you need to find that value you may try the below:

1. Logon to your ArcGIS Online organizational account.

2. Navigate to content, if you have any existing feature layer or if not you can search in your organization you should find any feature service or map service or any other ArcGIS Server services.

3. Go to the details page and scroll to the bottom of the page there will be a URL which will have the value you are looking for.

 

ManishPatel_0-1610576295968.png

 

Cheers,
Manish

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2 Replies
Esri Contributor

Hi @AmyWoods2 ,

 

What you are looking for might be not exactly documented. However, if you need to find that value you may try the below:

1. Logon to your ArcGIS Online organizational account.

2. Navigate to content, if you have any existing feature layer or if not you can search in your organization you should find any feature service or map service or any other ArcGIS Server services.

3. Go to the details page and scroll to the bottom of the page there will be a URL which will have the value you are looking for.

 

ManishPatel_0-1610576295968.png

 

Cheers,
Manish

View solution in original post

New Contributor

Thank you for the reply. I actually figured that out after I posted. Hopefully if someone comes with the same question they can find your response. Thanks!