Latest Contributions by JenniferNery

You can look at this thread - how to get graphic from selected row http://forums.arcgis.com/threads/46013-FeatureDataGrid-Selection-Changed-Event ... View more

When using Draw, note that DrawMode=Rectangle results to e.Geometry of type Envelope. You would want to convert this to Polygon geometry first.    var env = e.Geometry as Envelope;    Polygon p = new Polygon() { SpatialReference = env.SpatialReference };    PointCollection ring = new PointCollection();    ring.Add(new MapPoint(env.XMin, env.YMin));    ring.Add(new MapPoint(env.XMin, env.YMax));    ring.Add(new MapPoint(env.XMax, env.YMax));    ring.Add(new MapPoint(env.XMax, env.YMin));    ring.Add(new MapPoint(env.XMin, env.YMin));    p.Rings.Add(ring);    var graphic = new Graphic() { Geometry = p }; Also, you may want to call Simplify on the result geometry from Draw to ensure that the geometry is topologically correct before saving to your FeatureLayer. Editor.Add or TemplatePicker already does this for you if GeometryService has been provided (you can check this on Fiddler): http://help.arcgis.com/en/webapi/silverlight/samples/start.htm#ToolkitTemplatePicker. To call Simplify, you can look at this SDK sample: http://help.arcgis.com/en/webapi/silverlight/samples/start.htm#Simplify ... View more

Are you using FeatureDataGrid? If no and you are using this SDK sample: http://help.arcgis.com/en/webapi/silverlight/samples/start.htm#Identify, you can update the IdentifyGrid ScrollViewer by inserting the following code:       <StackPanel>       <slData:DataGrid x:Name="IdentifyDetailsDataGrid" AutoGenerateColumns="False" HeadersVisibility="None"                                Background="White">        <slData:DataGrid.Columns>         <slData:DataGridTextColumn Binding="{Binding Path=Key}" FontWeight="Bold"/>         <slData:DataGridTextColumn Binding="{Binding Path=Value}"/>        </slData:DataGrid.Columns>       </slData:DataGrid>        <slData:DataGrid x:Name="IdentifyDetailsDataGrid2" AutoGenerateColumns="False" HeadersVisibility="None"                                Background="White">         <slData:DataGrid.Columns>          <slData:DataGridTextColumn Binding="{Binding Path=Key}" FontWeight="Bold"/>          <slData:DataGridTextColumn Binding="{Binding Path=Value}"/>         </slData:DataGrid.Columns>        </slData:DataGrid>       </StackPanel>         public void ShowFeatures(List<IdentifyResult> results)         {             _dataItems = new List<DataItem>();              if (results != null && results.Count > 0)             {                 IdentifyComboBox.Items.Clear();                 foreach (IdentifyResult result in results)                 {                     Graphic feature = result.Feature;                     string title = result.Value.ToString() + " (" + result.LayerName + ")";                     _dataItems.Add(new DataItem()                     {                         Title = title,                         Data = feature.Attributes                     });                     IdentifyComboBox.Items.Add(title);       if(result.LayerId == 3)       IdentifyDetailsDataGrid.ItemsSource = feature.Attributes;      else       IdentifyDetailsDataGrid2.ItemsSource = feature.Attributes;                  }                 IdentifyComboBox.SelectedIndex = 0;             }         } Try this first and you will see that LayerId=3 is always displayed on top data grid. If this works for you, you can clean up other code and remove use of ComboBox. If you are using FeatureDataGrid, you need to put your results in 2 different GraphicsLayer. Same idea, use IdentifyResults.LayerId or LayerName to separate the results. ... View more