Python: If Then with Left Equivalent

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10-24-2017 07:35 AM
MichaelWalden
New Contributor

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Trying to calculate using Python in 10.3 the "Region" field with text based on the first two characters in a string field called "API_10".  Basically, if the left two characters in "API_10" equal "33", then populate "Region" with "North".

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JoshuaBixby
MVP Esteemed Contributor

API_10[0:2] or API_10[:2]

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JoshuaBixby
MVP Esteemed Contributor

API_10[0:2] or API_10[:2]

JoshuaBixby
MVP Esteemed Contributor

Also, just pass the whole column to your function since the function does slicing and checking:  Region = TextValue(!API_10!)

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MichaelWalden
New Contributor

Thanks Joshua!

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DanPatterson_Retired
MVP Esteemed Contributor

Joshua is correct... python slicing is 0 based and exclusive of the slice number, hence

whatever[:2] or whatever[0:2] will return 0 and 1.  The slice is [start:stop:step]

whatever = 'abcdefg'

whatever[0:6:2]
'ace'

whatever[:6:2]
'ace'

or skipping the start and stop

whatever[:6]
'abcdef'
TedKowal
Regular Contributor II

When you do a slice or substring in Python and  it starts with "0" then the second number is always the length.  This confused me for a while ..... https://www.dotnetperls.com/substring-python 

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DanPatterson_Retired
MVP Esteemed Contributor

Or the most succinct descriptor... the python docs 

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