Como recuperar o caminho do workspace a partir de uma camada usando arcpy?

Question

<\/HEAD>Jason Camerano<\/A> me deu este trecho de python:<\/P>head, <\/SPAN>sep<\/SPAN>, <\/SPAN>tail = arcpy.Describe(parcelFabricLayer).Path.partition(".gdb"<\/SPAN>) workspacePath = head + sep<\/SPAN><\/PRE>explicação:<\/P>Describe().Path retorna o caminho completo que também contém a string ".gdb"<\/P>partition separa usando a string fornecida ".gdb" <\/SPAN> para:<\/P>head - antes da string ".gdb"<\/SPAN><\/LI>sep - a string ".gdb"<\/SPAN><\/LI>tail - depois da string ".gdb"<\/SPAN><\/LI><\/UL><\/P>Alguém tem um método melhor?<\/P><\/BODY><\/HTML>

MattHowe · Answer

For Julian's path example I'd normally use os.

a = r"D:\Data\GISData\dataeceived\Transport.gdb\Routing\AccessRoad"
os.path.dirname(os.path.dirname(a))
'D:\Data\GISData\data\received\Transport.gdb'

MarkDonnelly · Answer

In Pro you can use the following:

layer.connectionProperties["connection_info"]["database"]

JulianInskip · Answer

Hi Amir. I do mine a little different. I don't use arcpy to get my workspace path. I find mine takes a lot quicker as it does not have to call arcpy every time, saving a few seconds. With this method you can also use any geodatabase type (.sde, .gdb or .mdb). accessRoadFc = r"D:\Data\GISData\data eceived\Transport.gdb\Routing\AccessRoad" wkspSplit = accessRoadFc.split(".") wkspExt = wkspSplit[1].split("\")[0] workspace = "{}.{}".format(wkspSplit[0], wkspExt)‍‍‍‍‍‍‍