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FeatureLayer.SelectFeature() - Polygon fill symbol (Colorize the area of a polygon)

OliverBrandt2

Hi all,

how can I fill the whole polygone after selecting it on a featureLayer? FeatureLayer supports only to highlight the lines of the polygon by default. In ArcMap it is possible to set a selection symbol, which allows to color the included area.

Do anybody have an idea to solve this?

Thank you guys!

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Accepted answers

AnttiKajanus1

Hi Oliver,

I think that you need to copy the feature as a graphic to GraphicsOverlay and define your custom selection symbol as a symbol for that one. Also you might want to hide the selected feature from the FeatureLayer using featureLayer.SetVisibility method. There is a bit more code involved with this approach but it gives you full control what is shown with what symbols and when.

All comments

OliverBrandt2

Thank you! This is an very interesting example, but we are using ArcGIS runtime for .NET.

I worked with Antti's approach.

My Code is:

var color = Color.FromArgb(150,140,235,240);

var selectionColor = new SimpleFillSymbol

{

Color = color

};

var selectedPolygon = GeodatabaseFeature.AsGraphic();

selectedPolygon.Symbol = selectionColor;

_MapView.GraphicsOverlays[PolygonGraphicsOverlayKey].Graphics.Add(selectedPolygon);

At my clearSelection method I clear the PolygonGraphicsOverlay as well. This works very good for me.

Anonymous User

Hi Oliver,

The following VBA sample is able to set the selection symbol to be solid green:

Public Sub SetSeleSymbol()

Dim pMxDoc As IMxDocument

Set pMxDoc = ThisDocument

Dim pMap As IMap

Set pMap = pMxDoc.FocusMap

Dim pFeatLayer As IFeatureLayer

Set pFeatLayer = pMap.Layer(0)

Dim featSel As IFeatureSelection

Set featSel = pFeatLayer

Dim polySym As ISimpleFillSymbol

Set polySym = New SimpleFillSymbol

Dim pColor1 As IRgbColor

Set pColor1 = New RgbColor

pColor1.Red = 0

pColor1.Green = 250

pColor1.Blue = 0

Dim pcolor2 As IRgbColor

Set pcolor2 = New RgbColor

pcolor2.Red = 0

pcolor2.Green = 0

pcolor2.Blue = 250

Dim pLineSym As ILineSymbol

Set pLineSym = New SimpleLineSymbol

pLineSym.Color = pcolor2

pLineSym.Width = 2

polySym.Color = pColor1

polySym.Outline = pLineSym

featSel.SetSelectionSymbol = True

Set featSel.SelectionSymbol = polySym

End Sub

Results will be like this:

OliverBrandt2

Hi Antti,

thanks for your response. Taking the geometry and creating a graphic out of it, is an good approach. I'll try this.

AnttiKajanus1

Hi Oliver,

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