GraphicElement Visibility

Question

import arcpy mxd = arcpy.mapping.MapDocument("CURRENT") # The text element is a textbox elm1 = arcpy.mapping.ListLayoutElements(mxd, "TEXT_ELEMENT", "closeup1")[0] if mxd.dataDrivenPages.currentPageID == 1: elm1.visible == True elif elm1 != 1: elm.visible == False if mxd.dataDrivenPages.currentPageID == 1: print "yes" elif mxd.dataDrivenPages.currentPageID <> 1: print "no"‍‍‍‍‍‍‍‍‍‍‍‍‍‍ ‍‍‍‍‍‍‍‍‍‍‍‍‍‍ Anyone familiar with Graphic Element Visibility property. It doesn't work for me. I used the print statements to verify current page which is working fine. I referenced http://pro.arcgis.com/en/pro-app/arcpy/mapping/graphicelement-class.htm and there isn't a good example.

DanPatterson_Retired · Answer

if mxd.dataDrivenPages.currentPageID == 1 elm1.visible = True else: elm.visible = False if elm1 != 1: # do something else: # do something else‍‍‍‍‍‍‍‍‍ your previous lines don't account for the possible combinations. ie they are separate questions and you are trying to do shortcuts. So if the current page id isn't 1... set elem1 visible... else, turn it off. Now if elm1 is not = 1 (don't even know if that is correct) do something, otherwise do something else

DevinUnderwood2 · Answer

Right, good catch. I am checking whether elm1(text element) appears while viewing page 1.

If so, make visible.

I changed it but still no luck.

DanPatterson_Retired · Answer

elm1.visible == True # this is an equality check... ie. is it visible???? elm1.visible = True # this is an assignment statement. ie. make it visible... # choose wisely a '=' makes a huge difference‍‍‍‍‍‍‍‍‍