python-toolbox: is it possible to define a function wihtin __init__ or execute?

nadja

is it possible to define a function wihtin __init__ or execute? if yes, how?

like this doesnot work:

class Toolbox(object):
def __init__(self):
self.label = "Toolbox"
self.alias = "toolbox"

self.tools = [Tool]

def myfunction():
[...]

 

 

also this doesnot work:

def execute(self, parameters, messages):
def myfunction():
[...]

Luke_Pinner

Yes. But you need to understand scope.  At it's simplest, functions (and variables) are objects and objects are only "visible" at (or below) the scope in which they are created.

So by creating a function inside the local scope of a method (e.g. __init__ or execute), you can only use that function inside the method you defined it in.

E.g.

class Tool(object):
    def __init__(self):
        def func_in_init():
            return "init"
    def execute(self):
        def func_in_exec():
            return "exec" 
        
        print(func_in_exec())  # this will work
        print(func_in_init())  # this will raise NameError
        

If you want to use a function anywhere, define it globally, if you want to use it anywhere in your Tool class and not outside the class, make it a method.