nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

replace characters label ArcMap

TomasLooström

Hey!
I wish to use replace twice in the same field.
Attributes: >0980>Visy> GA: 8 must be labeled GA:8.
I use def FindLabel ([externid]):
  return [externid] .replace ('0980>Visy', ''), but fails to add code so that even the last > disappear.
 Anyone know how to write it?
Best regards,
Tomas

Encontre mais publicações marcadas com

Accepted answers

Anonymous User

Is there some that contains spaces (> 0980> Visy>) and others that do not (>0980>Visy) in your field? If that is the case, I'd suggest using

[externid].split('>')[-1].strip()

Anonymous User

Without getting to regex, you can chain them with what you need.

.replace('>0980>Visy>', '').replace('>0980>Fran>', '')

If there are a lot, you can create a loop to iterate through all the variations from a list and replace them. Assuming there is a space there between the last > and GA:8,or you can find another way to parse out the part you want to replace.

for str in [str[0].split(' ')[0] for str in arcpy.da.SearchCursor(yourfc, [externid])]:
   [exernid].replace(str, '')

or index it as Jayanta provided.

[externid].split('>')[-1]

All comments

Anonymous User

Is there some that contains spaces (> 0980> Visy>) and others that do not (>0980>Visy) in your field? If that is the case, I'd suggest using

[externid].split('>')[-1].strip()

TomasLooström

When I use .replace ('> 0980> Visy>', '') .replace ('> 0980> Fran>', '') then> 0980>Visy is included in the labeling but last> disappears.

Anonymous User

Without getting to regex, you can chain them with what you need.

.replace('>0980>Visy>', '').replace('>0980>Fran>', '')

for str in [str[0].split(' ')[0] for str in arcpy.da.SearchCursor(yourfc, [externid])]:
   [exernid].replace(str, '')

or index it as Jayanta provided.

[externid].split('>')[-1]

JayantaPoddar

Check if a similar script works

Parser: Python

(!FieldName!.split(' ',1)[1]).replace(' ','')

TomasLooström

Thanks for the reply!

I missed writing that Visy can consist of different names, it varies and can then be Fran instead of Visy.

Anonymous User

replace replaces the whatever string you put in the first parameter so you need to be explicit with what you want replaced.

.replace('>0980>Visy>', '')

Participe da Conversa

Membros conectados podem postar, seguir atualizações e mais. Novo aqui? Registre uma conta gratuita.

Links Rápidos

Community Help
Find useful guides, FAQs, and documents to help you navigate and make the most of Esri Community.