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type of variables and the use of Moran's I

PinkOrchid

Hi everyone,

I am wondering if anyone can direct me towards a source where I can find an answer to this question: if the variable I am investigating for spatial autocorrelation is not continuous, is it still appropriate to use Moran's I?

I am referring to binary data (e.g. high versus low access to stores) or multinomial data (e.g., high, medium, and low access to stores). The textbooks I consulted indicate that Moran's I can be used for continuous, ordinal, and interval data. However, all examples concern continuous data. I read a paper looking at the spatial autocorrelation in an obesity variable (non-obese versus obese) for individuals living in the same area. I am not sure that is right, based on what I read.

Can someone help clarify this issue for me?
Thank you very much!

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Accepted answers

DanPatterson_Retired

There is the Joins Count test...but for the life of me I can't find a decent link other that in old text books

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DanPatterson_Retired

There is the Joins Count test...but for the life of me I can't find a decent link other that in old text books

PinkOrchid

Hello Dan,
Thank you very much for your answer. Yes, that is an option. However, I am mostly interested in looking at high-medium-low type of variables... so I do not know what to do.
Thanks!

PinkOrchid

Hello,

I am so sorry, I meant to click on "this answer was helpful"!!!!
please, administrators, could you correct it for me?
so sorry about that!!!!

PinkOrchid

There is the Joins Count test...but for the life of me I can't find a decent link other that in old text books

Hello,

For the Moderators: I would like to ask you if you could please verify that I marked the answer by Dan Patterson as helpful. I am not sure why the arrow down seems highlighted - I am not familiar with the forum's system of arrows. I was wondering if you could please make sure the way I marked the answer is consonant with the way I meant it, as I found it very helpful.

Thank you so much and I apologize for any inconvenience.
Dan, sorry about this and thanks again for your helpful reply!

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