nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

Python get two values in a Search Cursor than go to next line

deleted-user-MS0lE1F_0-sy

I am trying to write my getValues to a text element loop, but I want there to be two results per line before going to the new line. I am having trouble figuring it out? I think I might new a while loop perhaps instead of a for loop, and probably need to use next() somewhere? But that seems to just loop through each name and put one result instead of all four.

I don't want this: Anna I want this: Anna Ben

Ben Charlie Dora

Charlie

Dora

I don't know what to use in here to achive this.

rows = arcpy.SearchCursor(Layer)
        textValue = ""
        for row in rows:
            textValue += row.getValue(Value1) + ''
        ParcelText2.text = textValue
        del rows

Vind meer berichten getagd met

Accepted answers

TomSellsted

Matthew,

Just a bit of a logic error. This should work:

rows = arcpy.SearchCursor(Layer) 
textValue = ""
count = 1
for row in rows: 
    if (count%2): 
        textValue += row.getValue(Value1) + '  '   
    else: 
        textValue += row.getValue(Value) + '' 
    count +=  1

ParcelText2.text = textValue

Regards,

Tom

All comments

IanMurray

Matthew,

I wanted to recommend for future using of cursors that you use the new data access cursors(arcpy.da.SearchCursor e.g.). They are significantly faster than the old style cursors you were using in your code. The parameters and syntax are somewhat different from the cursors you were using, but still easy to use.

Here is the link for the new cursors versus old cursors.

ArcGIS Help (10.2, 10.2.1, and 10.2.2)

TomSellsted

Matthew,

Just a bit of a logic error. This should work:

rows = arcpy.SearchCursor(Layer) 
textValue = ""
count = 1
for row in rows: 
    if (count%2): 
        textValue += row.getValue(Value1) + '  '   
    else: 
        textValue += row.getValue(Value) + '' 
    count +=  1

ParcelText2.text = textValue

Regards,

Tom

deleted-user-MS0lE1F_0-sy

Ian/Tom,

I have tried the different versions and it still gets written like this: Anna & I want this: Anna Ben

Ben Charlie Dora

Charlie

Dora

rows = arcpy.SearchCursor(Layer)
textValue = ""
for row in rows:
     count = 1
     if (count%2) == 0:
          textValue += row.getValue(Value1) + '  '
          count += 1
      else:
          textValue += row.getValue(Value) + ''
          count +=  1
ParcelText2.text = textValue

DanPatterson_Retired

in fact you don't even need the equality test since it will either be 1 or 0

which equates to a Boolean without the danger of comparing to a number

>>> a = [ not(i%2) for i in range(11)]
>>> b = [ (i%2)== 0 for i in range(11)]
>>> a
[True, False, True, False, True, False, True, False, True, False, True]
>>> b
[True, False, True, False, True, False, True, False, True, False, True]
>>> a == b
True
>>>

TomSellsted

There are always lots of different ways to solve problems!

IanMurray

That was probably the better one to use, my general python gets rustier and rustier I feel like since I am only use python within the arcpy module these days(and with a limited usage at that!).

TomSellsted

Matthew,

Some logic like Ian describes will work. You can use the modulo operator to accomplish this too.

if (count%2) == 0:

Regards,

Tom

IanMurray

should be fairly easy to use a counter or something similar to check.

rows = arcpy.SearchCursor(Layer)  
textValue = ""  
for row in rows:  
    count = 1
    if count/2.0.is_integer() == False:
         textValue += row.getValue(Value1) + ' '
         count += 1
    else: 
         textValue += row.getValue(Value1) + '' 
         count += 1        
ParcelText2.text = textValue  
del rows

Doe mee aan het gesprek

Aangemelde leden kunnen berichten plaatsen, updates volgen en meer. Nieuw hier? Registreer een gratis account.

Snelle Links

Community Help
Find useful guides, FAQs, and documents to help you navigate and make the most of Esri Community.