I did this using a simple linear interpolation for the 30- and 40-degree values referenced in the table contained in the link. Does this seem like a sound way to determine the appropriate z-factor? If not, could anyone suggest an alternative?
z=1/(111320*COS(latitude*pi/180)) z=0.00001148 where latitude = 38.5
=1/(111320*COS(38.5*PI()/180))
=1/(111320*COS(RADIANS(38.5)))
Thank you both. Very helpful responses.
Aangemelde leden kunnen berichten plaatsen, updates volgen en meer. Nieuw hier? Registreer een gratis account.
Find useful guides, FAQs, and documents to help you navigate and make the most of Esri Community.