AGSLocatorTask ignores AGSGeocodeParameters.minScore

Question

let params = AGSGeocodeParameters()

params.maxResults = 100

params.resultAttributeNames = ["*"]

params.outputSpatialReference = mapView?.spatialReference

params.searchArea = mapView?.visibleArea?.extent

params.minScore = 95

cancelable = locatorTask.geocode(withSearchText: searchText, parameters: params) { [weak self] results, error in

for result in results {

log.error("result score = \(result.attributes?["Score"])")

}

I am using the code above to get matched [AGSGeocodeResult]. And I see:

❤️ ERROR | 2017-06-06 18:31:08.9130 |  result score = Optional(95.5)

❤️ ERROR | 2017-06-06 18:31:08.9150 |  result score = Optional(94)

❤️ ERROR | 2017-06-06 18:31:08.9180 |  result score = Optional(94)

❤️ ERROR | 2017-06-06 18:31:08.9200 |  result score = Optional(92.8)

❤️ ERROR | 2017-06-06 18:31:08.9220 |  result score = Optional(92.8)

❤️ ERROR | 2017-06-06 18:31:08.9230 |  result score = Optional(92.8)

So it's probably an issue with AGSLocatorTask? And what is default value for the AGSGeocodeParameters.minScore parameter?

NikolayYekimov · Answer

Thanks for the reply. Do you have an idea on why occasionally I receive less search results when I increase map's extent (visible area)? As an user I expect to receive more results when I zoom out, but in some cases receive less results (was 5 results with smaller extent and left only one after zooming out). My assumption was that the min score gets decreased and a result with low score gets filtered out but you say that the default min score is 0 and not used in the `online` geocoding.

MarkDostal · Answer

Thank you for your question!  The `minScore` property on `AGSGeocodeParameters` is for offline geocoding only.  For online geocoding, `minScore` has no effect.  The default value is 0.

A couple of quick tips:  The `AGSGeocodeResult` object has a `score` property, so you don't need to access the attributes to get at the score:

print("result score = \(result.score)")

Also, if you want to filter results based on the minScore, you can do this:

let filteredResults = results.filter { $0.score >= params.minScore }

I will get the doc updated to avoid future confusion.

If you have any more questions, let us know!

Mark