nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

QueryTask for dynamicLayer

tomwang1

Hi,

I am using ArcGISDynamicMapServiceLayer not FeatureLayer. I am wondering if there a way to query a dynamic layer while user clicks on map? Something likes:

var queryTask = new QueryTask(dynamicMapServiceUrl + "/dynamicLayer", {
"source": layerSource
});
var query = new Query();
query.geometry = clickedMapPoint

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Accepted answers

JianHuang

Yes, the code snippet that you have should work.

All comments

tomwang1

Thanks Huang Jian,

It was my mistake. QueryTask for dynamicLayer works fine with no problem!

JianHuang

Or, maybe you can create a simple reproducible case and put it on jsfiddle.net.

tomwang1

I am not sure how to post json of the layerSource? it is an object. I can see from Chrome console, there are too many object in side.

JianHuang

What is the layerSource got returned? Please post the json object.

tomwang1

Hi Huang Jian,

Nice to talk you again. I am not sure what I have be missing. I got this error message:

Uncaught TypeError: Object [object Object] has no method 'toJson'

If I change "dynamicMapServiceUrl/dynamicLayer" to "dynamicMapServiceUrl/2" to test my code, it works fine. Also the layerSource has no problem to draw on my map. Please advise!

function createQueryDataSourceLayer(mQuery) {
                  var m_queryDataSource = new esri.layers.QueryDataSource();
                  m_queryDataSource.geometryType = "polygon";
                  m_queryDataSource.oidFields = ["OBJECTID"];
                  m_queryDataSource.query = mQuery;
                  m_queryDataSource.spatialReference = new esri.SpatialReference({ wkid: 102100 });
                  m_queryDataSource.workspaceId = "myworkspace";
                  layerSource = new LayerDataSource();
                  layerSource.dataSource = m_queryDataSource;

                  return layerSource;
              }

JianHuang

Yes, the code snippet that you have should work.

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