Change selection color of graphics layer

EdwardSon

Is it possilbe to easily change selection color of graphics layer?
Feature layer has SelectionColor property but graphics layer does not.
Is there an easy or best way to accomplish this?

DominiqueBroux

You are right, unfortunately GraphicsLayer has no SelectionColor property.

The way to do it is by defining your own symbols with 'Selected' selectionStates.

As sample, here is how the X feature symbol is defined:

 
    <ControlTemplate x:Key="FS_SimpleMarkerSymbol_X">
        <Path x:Name="Ex"
              Stretch="Fill"
              Data="M0,1 L1,0 2,1 3,0 4,1 3,2 4,3 3,4 2,3 1,4 0,3 1,2 Z"
              Width="{Binding Symbol.Size}"
              Height="{Binding Symbol.Size}"
              RenderTransformOrigin="{Binding Symbol.RenderTransformPoint}"
              Fill="{Binding Symbol.Color}"
              Stroke="{Binding Symbol.OutlineColor}"
              StrokeThickness="{Binding Symbol.OutlineThickness}"
              StrokeDashArray="{Binding Symbol.OutlineStyle, Converter={StaticResource DashArrayConverter}}"
              StrokeLineJoin="Round">
            <Path.RenderTransform>
                <RotateTransform Angle="{Binding Symbol.Angle}"/>
            </Path.RenderTransform>
            <VisualStateManager.VisualStateGroups>
                <VisualStateGroup x:Name="SelectionStates">
                    <VisualState x:Name="Unselected" />
                    <VisualState x:Name="Selected">
                        <Storyboard>
                            <ObjectAnimationUsingKeyFrames Storyboard.TargetName="Ex"
                                Storyboard.TargetProperty="Fill">
                                <DiscreteObjectKeyFrame KeyTime="0:0:0" Value="{Binding Symbol.SelectionColor}" />
                            </ObjectAnimationUsingKeyFrames>
                        </Storyboard>
                    </VisualState>
                </VisualStateGroup>
            </VisualStateManager.VisualStateGroups>
        </Path>
    </ControlTemplate>