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Renderer fromJson

ClemensMöller

I want to load a renderer from a JSON-String, but nothing shows. I can't find any error in the JSON-String, so I have no idea what is going wrong.

var flurLayer = new FeatureLayer({

url: "...",

fields: ["art", "render_pro", "katalog"],

title: "Flurstuecke",

renderer: rendererJsonUtils.fromJSON(sr)

})

var sr = {

"type": "simple",

"symbol": {

"type": "esriSFS",

"style": "esriSFSSolid",

"color": [255, 255, 0, 0.5],

"outline": {

"type": "esriSLS",

"style": "esriSLSSolid",

"color": [0, 0, 255, 1],

"width": 1.0

}

"label": "",

"description": "",

"rotationType": "geographic",

"rotationExpression": ""

}

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Accepted answers

ClemensMöller

Found the solution: The color attribute accepts as alpha value values between 0 and 255, not just between 0 and . When I set a to 1, it was (almost) invisible, 255 makes it fully opaque.

All comments

ClemensMöller

Found the solution: The color attribute accepts as alpha value values between 0 and 255, not just between 0 and . When I set a to 1, it was (almost) invisible, 255 makes it fully opaque.

ClemensMöller

While trying to log the JSON-Object to the console, I noticed, that sr is already a JSON object, that's the right input object for fromJSON. JSON.parse creates a JSON-Object from a string, this would be the previous step. The JSON object ist not accepted as a renderer, because some attributes must have different values in the renderer object and in the JSON object (i.e. the symbol type is esriSFS vs. simple-fill). This conversion is made in fromJSON (i think )

AlexZotos

Sometimes using something simpler is the way to go. If you console.log() the JSON.parse result what does it do? It should print a JSON object to the console which should contain the elements that your JSON string contains

ClemensMöller

I tried it but it did not work. As I understand it, the fromJSON method is build exactly for what I try to achieve. To create a javascript object for arcgis from a JSON-String. Why should I use JSON.parse instead?

AlexZotos

If your JSON is a string you should use JSON.parse to make into an object for the feature layer.

Trying modifying this:

renderer: rendererJsonUtils.fromJSON(sr)

into this:

renderer: JSON.parse(sr)

ClemensMöller

Hi Ben,

thanks for your answer, but it didn't work. Ich put the declaration of the JSON-String before the declaration of the layer, but the map doesn't show the layer. I tested declaring the renderer in javascript and that worked, so the error must be somewhere in the JSON or fromJson, but I don't know where.

BenElan

Hi Clemens,

The JSON variable (sr) should be declared before the feature layer (flurLayer)

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