setFeaturesVisible not working

Question

I have a list of features that I want to set the visibility on for on a feature layer. I don't want to change the definition expression because I requery the layer periodically to get the latest attributes, I have to remove and readd the definition query. I do something like this, but I cant seem to get it to work. property var allFeatures: ({}) property var searchFeatures: ({}) property Layer queryLayer: null onLengthChanged: { searchFeatures = {} for (var i = 0; i < listModelFields.count; i++) { searchFeatures[id] = features[id] } queryLayer.setFeaturesVisible(searchFeatures) } ‍‍‍‍‍‍‍‍‍‍‍‍‍ The above snippet just shows where i am trying to apply the setFeaturesVisible. I basically have a search bar, that when the length changes, I want the visible features to change with the filter this search bar performs on the model. But with my list of features I cant seem to get them show or hide, in fact the code actually breaks. Has anyone tried this function.

JamesBallard1 · Answer

M Ka‌, There is an error in our documentation for that method. Please accept my apologies for this error. I also apologize for the delay in getting back to you on this. The method you're calling has a second argument that is not documented properly. void FeatureLayer::setFeaturesVisible(list<Feature> features, bool visible)‍ Does that work if you pass the second arg? FeatureLayer QML Type | ArcGIS for Developers We'll get this fixed up asap.

MKa · Answer

I tried using both ways and neither worked.  I feel like I am missing something, but I cant find an example of this anywhere.  I need to be able to do this as I just want features not to be visible and not remove them from the definition query.  Does anyone know of some code examples of this anywhere?  I looked through the entire qt samples and a quick internet search and I came up with nothing.  For now I have to remove the definition query before I search and refresh my layer, then add the query back in after the search returns all the features, this is suboptimal at best.

JamesBallard1 · Answer

Hi M Ka‌, Can you try using list objects in your code? This is an object searchFeatures = {} This is a list/array searchFeatures = [] Please try that and let us know if that gets it working for you.