makeRasterLayer_management

Question

Hello

im sitting over a probably simple problem since hours, but somehow i cant solve the problem

Im converting ascii to esri rasters in a separte Method (core of this method): this works fine
    arcpy.env.workspace = resultsPath
    arcpy.ASCIIToRaster_conversion(inRaster, outRaster, "FLOAT")

in another method, im trying to make Rasters and later .lyr files out of those created rasters:
def addRammsFiles(mxd, nameR):
    arcpy.env.workspace= targetPath
    for files in arcpy.ListRasters():
            rasterName = arcpy.Describe(files).name
            rasterPath = targetPath + "/" + rasterName
            arcpy.MakeRasterLayer_management(rasterPath , rasterName)
            #arcpy.SaveToLayerFile_management(rasterName, rasterPath + ".lyr")

Im always getting the Error 00582: Error occured during excecution. (The name of the raster is < 13)
Does someone have an idea why it doesnt work (it worked previously, with rasters from featureToRaster)

help would be DEEPLY appreciated!

qet

thomsh · Answer

yes im sure - and i also worked for me in previous scripts...

thx for ur answers, guess i will have to try and error a bit more 🙂

qet

curtvprice · Answer

one more (and hopefully last) question - why is it not possible to put a parameter to the MakeRasterLayer_management out_rasterlayer field:

for example:rasterPath = arcpy.Describe(files).catalogPath
rasterName = "test"
arcpy.MakeRasterLayer_management(rasterPath, rasterName)

i get this same Execution error 000582)
[000582 : Error occurred during execution.]

I don't know why it's failing for you. This has always worked for me. In fact I usually do it that way... are you sure that's where your script is failing?

000582 is an extremely generic error. Did you get another error message as well?

thomsh · Answer

Thx a lot! now it works 🙂
perfect idea!

one more (and hopefully last) question - why is it not possible to put a parameter to the MakeRasterLayer_management out_rasterlayer field:

for example:
rasterPath = arcpy.Describe(files).catalogPath
rasterName = "test"
arcpy.MakeRasterLayer_management(rasterPath, rasterName)

(i get this same Execution error 000582)

greetings, 
qet