¿Cómo recuperar la ruta del espacio de trabajo desde una capa usando arcpy?

Question

<\/HEAD>Jason Camerano<\/A> me dio este fragmento de python:<\/P>head, <\/SPAN>sep<\/SPAN>, <\/SPAN>tail = arcpy.Describe(parcelFabricLayer).Path.partition(".gdb"<\/SPAN>) workspacePath = head + sep<\/SPAN><\/PRE>explicación:<\/P>Describe().Path devuelve la ruta completa que también contiene la cadena ".gdb"<\/P>partition separa usando la cadena proporcionada ".gdb" <\/SPAN> para:<\/P>head - antes de la cadena ".gdb"<\/SPAN><\/LI>sep - la cadena ".gdb"<\/SPAN><\/LI>tail - después de la cadena ".gdb"<\/SPAN><\/LI><\/UL><\/P>¿Alguien tiene un método mejor?<\/P><\/BODY><\/HTML>

MattHowe · Answer

For Julian's path example I'd normally use os.

a = r"D:\Data\GISData\dataeceived\Transport.gdb\Routing\AccessRoad"
os.path.dirname(os.path.dirname(a))
'D:\Data\GISData\data\received\Transport.gdb'

MarkDonnelly · Answer

In Pro you can use the following:

layer.connectionProperties["connection_info"]["database"]

JulianInskip · Answer

Hi Amir. I do mine a little different. I don't use arcpy to get my workspace path. I find mine takes a lot quicker as it does not have to call arcpy every time, saving a few seconds. With this method you can also use any geodatabase type (.sde, .gdb or .mdb). accessRoadFc = r"D:\Data\GISData\data eceived\Transport.gdb\Routing\AccessRoad" wkspSplit = accessRoadFc.split(".") wkspExt = wkspSplit[1].split("\")[0] workspace = "{}.{}".format(wkspSplit[0], wkspExt)‍‍‍‍‍‍‍