How do I create a new label class using arcpy?

Per_Åke_MattiasWallin

I am using ArcPro 2.6 and I can modify existing label classes no problem. But what I want to do is to create a new label class using arcpy- I just cannot figure it out, what am I missing? All example’s I come across starts with listLabelClasses which assumes the class already exists.

Thanks.

DestinyKelley1

I have figured out a way to bypass the corruption of the CIM definition when attempting to create a new label class with ArcPy CIM.  To test this out, you can use any layer those default class is named "Class 1." Instead of using arcpy.cim.CreateCIMObjectFromClassName('CIMLabelClass','V2') or arcpy.cim.CIMLabelClass() as suggested by other users, I used cimObject.labelClasses.copy(). 

The code to try out is below:

 

import arcpy

p = arcpy.mp.ArcGISProject('CURRENT')
m = p.listMaps('Map')[0]
layer = m.listLayers("Your Layer Name Here")[0]
cimObject = layer.getDefinition('V2')
lblClasses = cimObject.labelClasses
    
for lblClass in lblClasses:
    if lblClass.name == "Class 1":
        nlc_index = cimObject.labelClasses.index(lblClass)
        lblClass_copy = cimObject.labelClasses.copy()[nlc_index]
        cimObject.labelClasses.append(lblClass_copy)
        layer.setDefinition(cimObject)
        break

cimObject = layer.getDefinition('V2')
lblClasses = cimObject.labelClasses        
        
for lblClass in lblClasses:
    if lblClass.name == "Class 1":
        nlc_index = cimObject.labelClasses.index(lblClass)
        if nlc_index != 0:
            lblClass.name = "Dummy"
            layer.setDefinition(cimObject)

 

Hope this helps other users!