I am trying to replace an ampersand with & in a label expression in ArcGIS Desktop 10.4.1 my current code is along these lines: define FindLable ( [ customer ] ) : return replace ( [ customer ] , '&' , '&' ) For some reason this throws the following error: "Global name replace is not defined." What is the correct format for this python code? I have also tried str.replace and Replace and string.replace. Thank you, James

James, try: def FindLabel ( [ Status ] ) : return [ Status ] . replace ( '&' , '&' )

nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

Python string replace in a label

TimFerguson

I am trying to replace an ampersand with & in a label expression in ArcGIS Desktop 10.4.1

my current code is along these lines:

define FindLable<SPAN class="punctuation token">(</SPAN><SPAN class="punctuation token">[</SPAN>customer<SPAN class="punctuation token">]</SPAN><SPAN class="punctuation token">)</SPAN><SPAN class="punctuation token">:</SPAN>
&nbsp;&nbsp;&nbsp; <SPAN class="keyword token">return</SPAN> replace<SPAN class="punctuation token">(</SPAN><SPAN class="punctuation token">[</SPAN>customer<SPAN class="punctuation token">]</SPAN><SPAN class="punctuation token">,</SPAN> <SPAN class="string token">'&'</SPAN><SPAN class="punctuation token">,</SPAN> <SPAN class="string token">'&amp;'</SPAN><SPAN class="punctuation token">)</SPAN>
<SPAN class="line-numbers-rows"><SPAN>‍</SPAN><SPAN>‍</SPAN></SPAN>

For some reason this throws the following error: "Global name replace is not defined."

What is the correct format for this python code?

I have also tried str.replace and Replace and string.replace.

Thank you,

James

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Accepted answers

MatthewDobson

James, try:

<SPAN class="keyword token">def</SPAN> FindLabel <SPAN class="punctuation token">(</SPAN> <SPAN class="punctuation token">[</SPAN>Status<SPAN class="punctuation token">]</SPAN> <SPAN class="punctuation token">)</SPAN><SPAN class="punctuation token">:</SPAN>
 <SPAN class="keyword token">return</SPAN> <SPAN class="punctuation token">[</SPAN>Status<SPAN class="punctuation token">]</SPAN><SPAN class="punctuation token">.</SPAN>replace<SPAN class="punctuation token">(</SPAN><SPAN class="string token">'&'</SPAN><SPAN class="punctuation token">,</SPAN> <SPAN class="string token">'&amp;'</SPAN><SPAN class="punctuation token">)</SPAN><SPAN class="line-numbers-rows"><SPAN>‍</SPAN><SPAN>‍</SPAN></SPAN>

All comments

TimFerguson

That was it. Thank you Mathew.

MatthewDobson

James, try:

<SPAN class="keyword token">def</SPAN> FindLabel <SPAN class="punctuation token">(</SPAN> <SPAN class="punctuation token">[</SPAN>Status<SPAN class="punctuation token">]</SPAN> <SPAN class="punctuation token">)</SPAN><SPAN class="punctuation token">:</SPAN>
 <SPAN class="keyword token">return</SPAN> <SPAN class="punctuation token">[</SPAN>Status<SPAN class="punctuation token">]</SPAN><SPAN class="punctuation token">.</SPAN>replace<SPAN class="punctuation token">(</SPAN><SPAN class="string token">'&'</SPAN><SPAN class="punctuation token">,</SPAN> <SPAN class="string token">'&amp;'</SPAN><SPAN class="punctuation token">)</SPAN><SPAN class="line-numbers-rows"><SPAN>‍</SPAN><SPAN>‍</SPAN></SPAN>

TimFerguson

For the record: I am actually using define FindLabel spelled correctly.

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