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how to get center coordinates from map viewer?

EricEagle

I figured that this one would be pretty easy, but I'm having trouble finding it via google.

How do I (with arcpy/python) get current map viewer center coordinates or corner coordinates?

I'm constructing geospatial URL queries, and I want the tool to automatically send the viewer center point, or the 4 corner coordinates, as part of the URL payload.

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Accepted answers

LukeWebb

mxd <SPAN class="operator token">=</SPAN> arcpy<SPAN class="punctuation token">.</SPAN>mapping<SPAN class="punctuation token">.</SPAN>MapDocument<SPAN class="punctuation token">(</SPAN>r<SPAN class="string token">"C:\Project\Project.mxd"</SPAN><SPAN class="punctuation token">)</SPAN>
df <SPAN class="operator token">=</SPAN> arcpy<SPAN class="punctuation token">.</SPAN>mapping<SPAN class="punctuation token">.</SPAN>ListDataFrames<SPAN class="punctuation token">(</SPAN>mxd<SPAN class="punctuation token">)</SPAN><SPAN class="punctuation token">[</SPAN><SPAN class="number token">0</SPAN><SPAN class="punctuation token">]</SPAN>&nbsp;&nbsp; <SPAN class="comment token">#the 1st data frame</SPAN>
<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent
<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent<SPAN class="punctuation token">.</SPAN>XMin
<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent<SPAN class="punctuation token">.</SPAN>XMax

<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent<SPAN class="punctuation token">.</SPAN>YMin
<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent<SPAN class="punctuation token">.</SPAN>YMax
<SPAN class="line-numbers-rows"><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN></SPAN>

All comments

ClintonDow1

Hello Eric,

If I understand you correctly you'll want to look at DataFrame Objects and its extent property (in 10.x) or Camera Objects (in Pro) which uses the getExtent() - Both of these should return an Extent Object from which you can get the XMin, Ymin, Xmax & Ymax properties from to figure out the center point.

EricEagle

Great! Thanks Luke!

LukeWebb

mxd <SPAN class="operator token">=</SPAN> arcpy<SPAN class="punctuation token">.</SPAN>mapping<SPAN class="punctuation token">.</SPAN>MapDocument<SPAN class="punctuation token">(</SPAN>r<SPAN class="string token">"C:\Project\Project.mxd"</SPAN><SPAN class="punctuation token">)</SPAN>
df <SPAN class="operator token">=</SPAN> arcpy<SPAN class="punctuation token">.</SPAN>mapping<SPAN class="punctuation token">.</SPAN>ListDataFrames<SPAN class="punctuation token">(</SPAN>mxd<SPAN class="punctuation token">)</SPAN><SPAN class="punctuation token">[</SPAN><SPAN class="number token">0</SPAN><SPAN class="punctuation token">]</SPAN>&nbsp;&nbsp; <SPAN class="comment token">#the 1st data frame</SPAN>
<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent
<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent<SPAN class="punctuation token">.</SPAN>XMin
<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent<SPAN class="punctuation token">.</SPAN>XMax

<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent<SPAN class="punctuation token">.</SPAN>YMin
<SPAN class="keyword token">print</SPAN> df<SPAN class="punctuation token">.</SPAN>extent<SPAN class="punctuation token">.</SPAN>YMax
<SPAN class="line-numbers-rows"><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN><SPAN>‍</SPAN></SPAN>

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