pass a list into requests.get()

Question

This gets one URL and prints it in XML format. import requests from bs4 import BeautifulSoup url = r'''https://secure.shippingapis.com/ShippingAPI.dll?API=Verify&XML=

2451 Avalon CtAurora IL

''' #get the webpage response = requests.get(url) #see if the URL has been correctly encoded r_url = response.text #parse the downloaded page to get a beautifulsoup object new_xml = BeautifulSoup(r_url, features = "xml").prettify() print(new_xml)‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍ ‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍>>>

2451 AVALON CT AURORA IL 60503 8574

>>>‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍ But, I have a list of URLs that need to be printed in XML format. Using this list how can I pass one item at a time into requests.get()? Link to text file. #text file that has all the URLs txtfile = r'C:\Users\jpilbeam\USPSAPIWCHDUpdateAll.txt' #convert text file into a list with open (txtfile) as f: x = (list(map(str.strip ,f.readlines())))‍‍‍‍‍‍‍‍‍‍‍

JoshuaBixby · Accepted Answer

If x is a list of URL strings from the text file, you just iterate over x passing each value to requests and printing it: for i in x: response = requests.get(i) ‍‍‍