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Creating Sequential Numbering Based off Zip Codes

NoahSeeton

Hi,

I need to calculate a set of unique identifiers that goes sequentially based off the zip code in another field. For example, if the zip code is 77059 I need it to take that number and in the Unique Identifier column I created output 77059.001, then 77059.002 etc. until it gets to the next zip code, and start again. I.e., if 77064 is next, it needs to call that number and start back at 77064.001. This is what I have so far but obviously it doesn't call in the field !ZipCode!, and that's what I've been struggling with. If someone could help with this it would be greatly appreciated.

# Calculates a sequential number
# More calculator examples at esriurl.com/CalculatorExamples
import arcpy
rec=0
def SequentialNumber():
    global rec
    pStart = 77041
    pInterval = .001
    if (rec == 0):
        rec = pStart
    else:
        rec = rec + pInterval
    return f"{round(rec, 3):.3f}"

Also, its been struggling to output 3 decimals after it gets to .009 for example, it outputs 0.01 and I need it in 3 decimals. Someone else suggested the return f"{round(rec, 3):.3f}" code, but it seems to only work at times.

Noah

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Clubdebambos

Here's a blog post that walks you through creating a tool in ArcGIS Pro: it would need a slight tweak to use a "." instead of a "-" for the separator.

https://learn.finaldraftmapping.com/sequentially-increment-numbered-values-in-arcgis-pro-with-arcpy/

Hayden Welch

I'd just use a .zfill():

codes: dict[int, int] = {}
def SequentialNumber(code) -> str:
    global codes
    codes.setdefault(code, 0)
    codes[code] += 1
    return float(f"{code}.{str(codes[code]).zfill(3)}")

You also can't use a float for this as the __repr__ of a float always removes the trailing zeroes. You need to string format it.

You also REALLY don't want to be adding a value to the zip code. If you happen to add 0.001 1000 times, suddenly 77829 is 77830. Use a mapping with a counter if you need to preserve the zipcode.

To use this in the window you need to pass the zipcode field value to the function:

NoahSeeton

Hi,

Sorry for the dumb question but I'm really not that well versed in Python (or any coding languages for that matter). What do you mean by "Then def sequential_id(current_zip) int the "field" = def sequential_id(current_zip)".

Noah

Tonyalmeida

Try this, Paste the code above into the "Code Block"

Then def sequential_id(current_zip) int the "field" = def sequential_id(current_zip)

Code

zip_counts = {}
prev_zip = None

def get_sequential_id(current_zip):
    global zip_counts, prev_zip
    
    # Convert zip to string
    current_zip = str(current_zip)
    
    # If new zip code, reset the counter
    if current_zip != prev_zip:
        zip_counts[current_zip] = 0
        prev_zip = current_zip
    
    # Increment the counter for this zip code
    zip_counts[current_zip] += 1
    
    # Format 3 decimal places
    return f"{current_zip}.{zip_counts[current_zip]:03d}"

danretired

The zipcode field isn't the one that is sorted, so a field calculator expression won't work nicely.

TableToNumPyArray, and arcpy's ExtendTable can be used to process data outside

So to fake some of your data.

# --- emulating your data column
seq
Out[113]: 
['77070',
 '77070',
 '77070',
 '77064',
 '77070',
 '77064',
 '77065',
 '77070',
 '77070',
 '77075']
# -- notice not ordered nicely
# I created an IDs and Code column in the subsequent section, here is
# what TableToNumPyArray will produce

arr
array([(0, '77070'), (1, '77070'), (2, '77070'), (3, '77064'), (4, '77070'), (5, '77064'), (6, '77065'), (7, '77070'),
       (8, '77070'), (9, '77075')], dtype=[('IDs', '<i8'), ('Code', '<U20')])

The ids and the data values are created, It is now a matter of finding the unique code values, getting the number of times they exist in the column and producing a sequence to append to them.

ids = np.arange(10, dtype='int')
dt = [('IDs', '<i8'), ('Code', 'U20')]
arr = np.asarray(list(zip(ids, seq)), dtype=dt)

u, idx, cnts = np.unique(arr['Code'], return_index=True, return_counts=True)  # get the unique, counts etc
tmp = [list(zip([u[i]] * cnts[i], np.arange(cnts[i]))) for i in range(len(cnts))]
app = np.concatenate(tmp)
out = []
for i in app:
    out.append("{}.{:0>3}".format(i[0], i[1]))

final_arr = np.copy(arr)
final_arr['Code'] = final
final_arr

At this point you have

final_arr.tolist()  # your IDs and reformatted Code values
[(0, '77064.000'),
 (1, '77064.001'),
 (2, '77065.000'),
 (3, '77070.000'),
 (4, '77070.001'),
 (5, '77070.002'),
 (6, '77070.003'),
 (7, '77070.004'),
 (8, '77070.005'),
 (9, '77075.000')]

# -- as a numpy array to use with arcpy.ExtendTable....
final_arr
Out[115]: 
array([(0, '77064.000'), (1, '77064.001'), (2, '77065.000'), (3, '77070.000'), (4, '77070.001'), (5, '77070.002'),
       (6, '77070.003'), (7, '77070.004'), (8, '77070.005'), (9, '77075.000')],
      dtype=[('IDs', '<i8'), ('Code', '<U20')])

Sorry I don't have ArcGIS Pro any longer so some other keener will have to fluff out the TableToNumPyArray and ExtendTable for you.

Orrrr you could continue to do the stuff in Excel and join back, which is essentially what this does but in a different way.

NoahSeeton

Hi Dan,

Thanks for responding. I only have a basic understanding (if you can call it that) of python so excuse me for the question, but how would I make this a float? I want to take the Zip Code column and create a new column with decimals. It will look like the second image I've attached, but that was done in excel then joined after. Ideally, I'd like to do it all in ArcGIS if possible.

To answer your question, they have been sorted prior to this and I'll attach a screenshot below.

Zip_Code_Ordered .png

Noah

danretired

rec = 12335.0123
type(f"{round(rec, 3):.3f}")
str

If your input zipcode is not text to begin with, the script you are using isn't going to provide you with what you want. If it is text, then it needs to be converted to float, incremented, formatted then converted back to text. I am not seeing that.

Also, are the zipcode data sequential always? (eg, data has been sorted physically prior to being worked on).

If they are not sequential and continuous without breaks, then there are other steps that need to be done

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