SegmentMeanShift function requires Output Raster Dataset?

Question

Hi all, I am fairly new to using ArcGIS Pro, but I am slightly experienced in Python in general. I'm not sure if this is the exact place to post this question, but I am stuck. I have successfully used ArcPy to clip a raster from a shapefile, and I now want to perform the SegmentMeanShift() function on said clipped raster. This process works in ArcGIS Pro, and I would like to have a script to automate this process for many different rasters. Below is the snippet of my code that gives me issues (most of it was copied from the documentation here) # script to clip and segment a raster # import libraries import arcpy import matplotlib.pyplot as plt import numpy as np import os from arcpy.sa import * #%% Clip raster in_ras = r"data\s20180403.tif" clip_ras = in_ras[:5] + r"clip_ras\" + in_ras[5:-4] + r"_clip.tif" feature_template = r"shapefiles\square_domain_0723.shp" arcpy.Clip_management( in_ras, "#", clip_ras, feature_template, "0", "ClippingGeometry") #%% Segment raster #check for spatial analyst license arcpy.CheckOutExtension("Spatial") # segment mean shift the clipped raster spec_detail = "10" spat_detail = "10" min_seg_size = "20" band_indexes = "1" seg_clip_ras = r"data\seg_clip_ras\" + "s20180403" + "_clip_seg.tif" seg_ras = SegmentMeanShift(in_ras, spec_detail, spat_detail, min_seg_size, band_indexes) seg_ras.save(seg_clip_ras)‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍ The output I receive from running this chunk of the script is: Traceback (most recent call last): File "", line 11, in spat_detail, min_seg_size, band_indexes) File "D:\ArcGISPro\Resources\ArcPy\arcpy\sa\Functions.py", line 7768, in SegmentMeanShift band_indexes) File "D:\ArcGISPro\Resources\ArcPy\arcpy\sa\Utils.py", line 53, in swapper result = wrapper(*args, **kwargs) File "D:\ArcGISPro\Resources\ArcPy\arcpy\sa\Functions.py", line 7761, in Wrapper band_indexes) File "D:\ArcGISPro\Resources\ArcPy\arcpy\geoprocessing\_base.py", line 506, in return lambda *args: val(*gp_fixargs(args, True)) ExecuteError: Failed to execute. Parameters are not valid. ERROR 000735: Output Raster Dataset: Value is required Failed to execute (SegmentMeanShift).‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍ I am unsure what is happening here, when I try to add another argument, the error says that SegmentMeanShift() only takes 5 arguments, not 6, which makes sense and is what I thought originally. So why is a value required for Output Raster Dataset? Basically, when this script is finished, I would like a raster saved in my directory that is clipped and segmented from the first raster. I have looked over the documentation and other questions and I cannot seem to find this specific issue. Thanks for help in advance, I have been stuck on this for awhile now.

JosephFogarty · Answer

Hi Dan, Thanks for the reply. 'data' simple refers to a folder named data. I have created an environment after I imported the libraries in the code above, something along the lines of: arcpy.env.workspace = "D:\my\project\path"‍‍ but I have omitted this line for anonymity. Yes, I am working locally on my computer. I think the path works fine, because the program is able to clip the raster, but not segment it.

DanPatterson_Retired · Answer

seg_clip_ras = r"data\seg_clip_ras\" + "s20180403" + "_clip_seg.tif"

your path... what does 'data' refer to? or are you just anonymizing your actual path? (ie you have no drive specification, if you are working locally)