nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

arcpy.mapping.AddLayer (SDE Feature Class)

JamesCrandall

When adding an ArcSDE Feature Class to an .mxd, it only shows the first 3 letters of the name in the TOC.

     arcpy.env.workspace = "C:\\Users\\me\\AppData\\Roaming\ESRI\\Desktop10.1\\ArcCatalog\\mysdeserver.sde"     sdelist = arcpy.ListFeatureClasses()     for sdeFC in sdelist:         ## locate the desired fc and add it to the TOC         if sdeFC == 'GIS.THE_FEATURE_CLASS_NAME':             sdeLyr = arcpy.mapping.Layer(sdeFC)             arcpy.mapping.AddLayer(df, sdeLyr, "BOTTOM")             arcpy.mapping.AddLayer             arcpy.RefreshTOC()

The above code adds the feature class but it adds it with the name "GIS". Am I completely using the wrong method (I don't see any other way). Solution? Comments?

Thanks!

Finde mehr Beiträge mit dem Tag

Accepted answers

MathewCoyle

I think you want to use MakeFeatureLayer and add that as a layer object to your map.

http://resources.arcgis.com/en/help/main/10.1/index.html#//00170000006p000000

All comments

JamesCrandall

** Changes applied and resolved **

Thanks again for your suggestions. I wasn't completely sold on the idea of using the MakeFeatureLayer_management function to load the SDE Feature Class and I revisted my initial approach. So, this actually did work at first ("sort of"):

arcpy.mapping.AddLayer(df, theFC, "BOTTOM")

The problem is that when it loaded into the TOC, it was named only with the first couple of characters of the full FC datasource. After thinking about it, I figured that maybe I could just simply rename it to the full name after it loads. And that seems to work for my needs -- just reseting the .name property is fine:


arcpy.env.workspace = "C:\\Users\\me\\AppData\\Roaming\ESRI\\Desktop10.1\\ArcCatalog\\mysdeserver.sde"
    sdelist = arcpy.ListFeatureClasses()
    for sdeFC in sdelist:
        ## locate the desired fc and add it to the TOC
        if sdeFC == 'GIS.THE_FEATURE_CLASS_NAME':
            sdeLyr = arcpy.mapping.Layer(sdeFC)
            arcpy.mapping.AddLayer(df, sdeLyr, "BOTTOM")
            arcpy.mapping.AddLayer
            ## reset the fc's name after it is added to the TOC
            arcpy.mapping.ListLayers(mxd)[0].name = "GIS.THE_FEATURE_CLASS_NAME"
            arcpy.RefreshTOC()

JamesCrandall

That all seems fine, what is the error message you get?

Didn't notice this until now, but arcgisscripting???? What? That is very odd.

arcgisscripting.ExecuteError: Failed to execute. Parameters are not valid.
ERROR 000733: Output Layer: Same as input C:\\Users\\me\\AppData\\Roaming\ESRI\\Desktop10.1\\ArcCatalog\\mysdeserver.sde\GIS.THE_FEATURE_CLASS_NAME
Failed to execute (MakeFeatureLayer)

From ArcGIS 10.1 Help:

"000733 : <value>: Same as input <value>.
Description
The input and output have been given the same name.

Solution
To prevent overwriting your input during the operation, change the output name to be unique from the input."

MathewCoyle

That all seems fine, what is the error message you get?

JamesCrandall

I'm not sure why you would have an issue with using the qualified name. I don't get any error when using the same layer name as the feature class name. How are you creating your mxd and df objects?

def onRectangle(self, rectangle_geometry):
  mxd = arcpy.mapping.MapDocument("CURRENT")
  df = arcpy.mapping.ListDataFrames(mxd)[0]

MathewCoyle

I'm not sure why you would have an issue with using the qualified name. I don't get any error when using the same layer name as the feature class name. How are you creating your mxd and df objects?

JamesCrandall

I think you want to use MakeFeatureLayer and add that as a layer object to your map.

http://resources.arcgis.com/en/help/main/10.1/index.html#//00170000006p000000

Ah. Okay that works (sort of). I get an error if I attempt to set the same fully qualified Feature Class name as it is in SDE. This fails:

if sdeFC == 'GIS.THE_FEATURE_CLASS_NAME':
   sdeLyr = arcpy.mapping.Layer(sdeFC)
   arcpy.MakeFeatureLayer_management(sdeFC, "GIS.THE_FEATURE_CLASS_NAME")

why would I want to add something to the map display that is NOT named what it is stored as?

Also: Why is it "MakeFeatureLayer"? This is not very descriptive of "Adding a Feature Class to the TOC"! Lol...

MathewCoyle

I think you want to use MakeFeatureLayer and add that as a layer object to your map.

http://resources.arcgis.com/en/help/main/10.1/index.html#//00170000006p000000

Nimm an der Unterhaltung teil

Angemeldete Mitglieder können Beiträge verfassen, Updates folgen und mehr. Neu hier? Registriere ein kostenloses Konto.

Schnellzugriffe

Community Help
Find useful guides, FAQs, and documents to help you navigate and make the most of Esri Community.