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Uunable to use 'arcpy.env.workspace' properly !

AdelItani

arcpy.env.workspace doest not work when we use barename for input file ?

# arcpy10.py
# CPython 2.6, ArcGIS 10, IDLE, windows_XP

import arcpy, sys
import arcpy.mapping
from arcpy import env
arcpy.env.overwriteOutput = True

arcpy.env.workspace = "d:\\test"

# Fullpath of input file.
arcpy.FloatToRaster_conversion(
"d:\\test\\14605430.flt",
"14605430.tif")

try:
# No fullpath of input file.
arcpy.FloatToRaster_conversion(
"14605430.flt",
"14605430.img")

except:
print arcpy.GetMessages()
sys.exit()

"""
Converting floating point file to grid ...
Executing: FloatToRaster 14605430.flt d:\test\14605430.img
Start Time: Sun Apr 01 12:58:49 2012
Failed to execute. Parameters are not valid.
ERROR 000865: Input floating point raster file: 14605430.flt does not exist.
Failed to execute (FloatToRaster).
Failed at Sun Apr 01 12:58:49 2012 (Elapsed Time: 0.00 seconds)
"""

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DarrenWiens2

I tried your code with the same result (it didn't work when setting the workspace environment). I don't have any explanation, perhaps someone from ESRI can speak to this.

You can fake a workspace environment with the following (it's basically just using the whole path):

import arcpy
import arcpy.mapping
workspace = "d:\\test\\"
arcpy.env.overwriteOutput = True

try:
    arcpy.FloatToRaster_conversion(
        workspace + "p4605430.flt",
        workspace + "p4605430.tif")
except:
    print arcpy.GetMessages()

AdelItani

Thanks Darren

I included zip-file 'p4605430_flt.zip' with files 'p4605430.flt' and 'p4605430.hdr',
and i am still facing the same error, after changing the line to:

arcpy.FloatToRaster_conversion("p4605430.flt", "p4605430.tif")

Where it does work properly with full_path_name without workspace environment.

p4605430_flt.zip

DarrenWiens2

Does it happen to work if you change the name so it doesn't start with a number? I don't know about .flt or .tif, but some file formats don't like that.

Also, does it work properly if you use the entire filename rather than relying on the workspace environment?

AdelItani

Yes Daren, there is two files: d:\test\14605430.flt, d:\test\14605430.hdr

Besides that, this script with replacing arcpy by arcgisscripting,
and with small editing, was run succefully on ArcGIS 9.2 and 9.3 .

DarrenWiens2

"The file must have a .flt extension. There must be a header file in association with the floating-point binary file, with a .hdr extension."

Does your .flt have an associated .hdr file?

AdelItani

Thanks Stacy for help, but i still have ERROR

import arcpy
import arcpy.mapping
arcpy.env.workspace = "d:\\test"
arcpy.env.overwriteOutput = True

try:
    arcpy.FloatToRaster_conversion(
        "14605430.flt",
        "14605430.tif")
except:
    print arcpy.GetMessages()

""" ERROR 010158: Unable to open file \14605430.flt.
ERROR 010067: Error in executing grid expression.
"""

StacyRendall1

There are two ways of accessing submodules (arcpy is a module, env (arcpy.env) is a submodule). In your code you are mixing them up, which is at least going to cause some issues...

Because you used:

from arcpy import env

Env is imported as its own module, so later on you should access it with:

env.workspace = "d:\\test"

The other way to do it is just:

import arcpy

Env is still a submodule of arcpy, so later on you should access it with:

arcpy.env.workspace = "d:\\test"

After that you should use the Not Full path method you have shown in your original post...

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