nav[aria-label="Primary Navigation"] { padding: 0; & ul { list-style: none; width: 100%; display: flex; flex-direction: row; justify-content: start; align-items: start; gap: 30px; padding: 0; & li { margin: 0; } & ul li { list-style: none; } } }

How to label with multiple fields when some are empty

LarissaBoundy

Hello,

I am using ArcGIS Pro and trying to get labels in a sensible way. The layer and variables I am using to create labels can have up to five classes (Regional Ecosystems, three in the screen shot below).

I have tried [$feature.RE1 +"/"+$feature.RE2+"/"+ $feature.RE3], which gives the below result, my issue being that when there was only one RE, there are is now // after the label which obviously looks silly.

Is there a way to get the extra RE labels and / to only appear if the field is not empty?

Thank you.

Finde mehr Beiträge mit dem Tag

Accepted answers

JayantaPoddar

alright. Check this one (Python)

(([RE1]+'/'+[RE2]+'/'+[RE3]).rstrip('/ / ')).rstrip('/')

([RE1]+'/'+[RE2]+'/'+[RE3]).replace('/ /','')

All comments

LarissaBoundy

Thank you everyone, Jayanta's suggestion below was successful!

(([RE1]+'/'+[RE2]+'/'+[RE3]).rstrip('/ / ')).rstrip('/')

MicZatorsky_AEC

IlkaIllers1 handling of None is important. Null requires special handling.
Null in the attribute table means None in python.
And None plus anything equals None

JohannesLindner

var raw_re = [$feature.RE1, $feature.RE2, $feature.RE3, $feature.RE4, $feature.RE5]
var filled_re = []
for(var i in raw_re) {
  if(!IsEmpty(raw_re[i])) {
    Push(filled_re, raw_re[i])
  }
}
return Concatenate(filled_re, "/")

IlkaIllers1

Well, I was foiled by my own data! Turns out it does work when you check that fields are really None (<Null>) instead of empty! This is my failsafe expression:

def FindLabel ([RE1],[RE2],[RE3]):
a = [RE1]
b = [RE2]
c = [RE3]
return "/".join([str(i) for i in [a, b, c] if i is not None and i !=""])

IlkaIllers1

Sorry, I just tried it and realised it doesn't work with "/". It still has the unwanted extra //. Curious! The same code with ", " instead works fine for me. I don't know why, sorry!

def FindLabel ([RE1],[RE2],[RE3]):
a = [RE1]
b = [RE2]
c = [RE3]
return ", ".join([str(i) for i in [a, b, c] if i is not None])

IlkaIllers1

I use something like this in the advanced expression of Python:

def FindLabel ([RE1],[RE2],[RE3]):
a = [RE1]
b = [RE2]
c = [RE3]
return "/".join([str(i) for i in [a, b, c] if i is not None])

HuubZwart

Not the most elegant solution, but you could employ the removeEmpty parameter from Split (Arcade). I.e. concatenate the values using Concatenate, split the new string with the removeEmpty parameter set and then concatenate again to get your label.