select by location using "layer URL" instead of layer name

Question

Hy guys, is there any way to use the select by location tool (via python) but using layer URL not layer name
eg: arcpy.SelectLayerByLocation_management(URL layer1"CROSSED_BY_THE_OUTLINE_OF",URL layer2,"","ADD_TO_SELECTION")
also I want to use searchCursor and updateCursor using Layer URL not layer name
I mean by URL, the REST URL of my layer service on arcgis online
I am using ArcGis Pro
Thank you

ChuckBenton · Answer

Did you ever resolve this?  I'm having a similar issue, and the online layer is massive (167M+ records) so copying isn't practical. See https://community.esri.com/t5/arcgis-api-for-python-questions/select-by-location-from-online-feature-layer-using/m-p/1087610#M6462 for details.

JoeBorgione · Answer

This morning I was able to use arcpy commands easily by simply referring to a feature layer's url: import arcpy fc = r'https://www.my.org/gisfed/rest/services/###/FeatureServer/9' for f in arcpy.ListFields(fc): print(f.name) with arcpy.da.SearchCursor(fc,'*') as cursor: for row in cursor: print(row) # both work as expected from a spyder console... ‍‍‍‍‍‍‍‍‍‍‍‍

JoshuaBixby · Answer

This can all be done using ArcPy.  Just use Make Feature Layer—Data Management toolbox | Documentation to make a layer first and then run your selection against it.  If you are running a standalone script outside of ArcGIS Pro, use SignInToPortal—ArcPy Functions | Documentation to authenticate your Python session first.