Jak získat cestu k pracovnímu prostoru z vrstvy pomocí arcpy?

Question

<\/HEAD>Jason Camerano<\/A> mi dal tento pythonový úryvek:<\/P>head, <\/SPAN>sep<\/SPAN>, <\/SPAN>tail = arcpy.Describe(parcelFabricLayer).Path.partition(".gdb"<\/SPAN>) workspacePath = head + sep<\/SPAN><\/PRE>vysvětlení:<\/P>Describe().Path vrací úplnou cestu, která také obsahuje řetězec ".gdb"<\/P>partition odděluje pomocí poskytnutého ".gdb" <\/SPAN>řetězce na:<\/P>head - před ".gdb" řetězcem<\/SPAN><\/LI>sep - ".gdb" řetězec<\/SPAN><\/LI>tail - za ".gdb" řetězcem<\/SPAN><\/LI><\/UL><\/P>Někdo má lepší metodu?<\/P><\/BODY><\/HTML>

MattHowe · Answer

For Julian's path example I'd normally use os.

a = r"D:\Data\GISData\dataeceived\Transport.gdb\Routing\AccessRoad"
os.path.dirname(os.path.dirname(a))
'D:\Data\GISData\data\received\Transport.gdb'

MarkDonnelly · Answer

In Pro you can use the following:

layer.connectionProperties["connection_info"]["database"]

JulianInskip · Answer

Hi Amir. I do mine a little different. I don't use arcpy to get my workspace path. I find mine takes a lot quicker as it does not have to call arcpy every time, saving a few seconds. With this method you can also use any geodatabase type (.sde, .gdb or .mdb). accessRoadFc = r"D:\Data\GISData\data eceived\Transport.gdb\Routing\AccessRoad" wkspSplit = accessRoadFc.split(".") wkspExt = wkspSplit[1].split("\")[0] workspace = "{}.{}".format(wkspSplit[0], wkspExt)‍‍‍‍‍‍‍