Why isn't this label code working?

Question

I've got a bunch of OpenStreetMap content that I'm trying to label (ArcGIS Pro 2.2.4) based on whether content is found in the other_tags field. Here's what I'm trying to do in the expression editor (Python): def FindLabel ( [other_tags] ): import re ls = [other_tags] slabel = re.search('"name:en"=>"(.*?)","', ls) return slabel.group(1)‍‍‍‍‍ It says "NameError: name 'FindLabel' is not defined Which is weird because if I remove the "," from the regex operation and do this: def FindLabel ( [other_tags] ): import re ls = [other_tags] slabel = re.search('"name:en"=>"(.*?)"', ls) return slabel.group(1) ‍‍‍‍‍ it renders as valid, although it prints out everything beyond the "name:en"=>" string. I have also tried this, which validates but returns nothing: def FindLabel ( [other_tags] ): ss = [other_tags] ls = ss[ss.find('"name:en"=>"')+1:ss.find('"')] return ls‍‍‍‍ Here is a bit of the sort of substring someone could expect to find in OSM's other_tags: "int_name"=>"Dubai","is_in:continent"=>"Asia","is_in:country_code"=>"AE","name:en"=>"Dubai","population"=>"1984000"....‍ Can anyone help me to get this label expression working?

EricEagle · Answer

Mark, thanks for the reply - I went and typed it back in from scratch, and it worked - what can I say, regex is tricky sometimes, though my face is a bit red for submitting a question that ultimately was due to my own typo!!

Mark Bockenhauer · Answer

Eric,

I was curious about this one and using ArcGIS Pro 2.3  I see the following:

seems to work?

2.3 will be available soon.

Mark