How to read parameter from a url

x_d

I want to know how to open specific screen in my app , when some qrcode read from my mobile camera ,and that qrcode contains, a url (my website link) + some parameter. currently I can only open home page of my app, when i try to read qrcode through mobile camera. How can i read the parameter from the url? Please do reply it's urgent

I have tried this 

onOpenUrl: {
    console.log("onOpenUrl:", url);

    var urlInfo = AppFramework.urlInfo(url);

    if (!urlInfo.host.length) {
        console.log("onOpenUrl parameters:", JSON.stringify(urlInfo.queryParameters, undefined, 2));
    }
}
urlInfo is blank and "onOpenUrl parameters:" consoles undefind 

 

x_d

@ErwinSoekianto  Thanks for your reply. And I'm getting the expected url, but when I'm trying to split the parameter from the url then it's not working.

 can you suggest me how to get separate the parameter from the url and then redirect to next page

onOpenUrl: {
         console.log("Open url is:"+url)//suppose the url contains 
                  "https://www.arcgis.com/home/index.html+refno=12345"
         var ref_no= url.split('=')[1]; //to grab my required parameter which is 12345
console.log("REF No Returns:"+ref_no)// it prints nothing total blank 
StackView.push("new_page.qml");        
}