Hello!
I could really use some help with a function. I have no experience with phyton and this seems like it could be fairly difficult.
I am trying to label my features. I have a field [trakt] from which i would like to extract the first letter, and if there is a space, I would also want to extract the first letter after that space.
The field [trakt] has names in it, for example it could be "South Sweden", "North Sweden" and "Sweden". If the name is "North Sweden" I would like the script to return "NS", but if the name is "Sweden", the script should return only "S". But in reality I have about 50 different names I would like to do this with (edited).
Is this problem possible to solve?
verbose so you can follow
python parser,
`a` is your field as an example
code block
a = ["South Sweden", "North Sweden", "Sweden"]
def sp(fld):
if " " in fld:
spl = fld.split(" ")
return spl[0][0] + spl[1][0]
else:
return fld[0]
[sp(i) for i in a]
['SS', 'NS', 'S']
calculator expression
sp(!trakt!)
Oh thank you! But if I have 50 names rather than just 3, is there a way to do this generally, or do I have to specify all 50 ?
It will do it for all. This is a field calculator function